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Edexcel AS/A2 Mathematics M2 - 17th June 2016 - Official Thread

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Reply 380
Avatar for Reda2
Reda2
14
Original post by Squishy•
Do errors get carried forward? Like I used 0.x instead of X for a calculation and it changed all my answers up


Yes you will probably get the method marks.
Original post by linaxq
so 73.3 and 10.44 no marks?


73.3 was right -- that's 3sf.

Which question was 10.44? You may only lose 1 mark if it involved g
Original post by linaxq
is 10.4 right ? are you talking about the value being wrong or sig figs


10.4 is right but 10.44 is wrong if you leave it at 4 s.f
How do you find lambda?
Original post by SHJBHB
For Q4a) I got the 0.8299 but managed to round it to 0.823 so will I just lose the 1 accuracy mark or will they see the 0.8299 and not look past it as it's the correct answer


I'm not entirely sure, I'd guess -1A though.
Reply 385
Avatar for linaxq
linaxq
2
Original post by Khoinet
10.4 is right but 10.44 is wrong if you leave it at 4 s.f


cant remember if i did 10.44 or 10.4 i might of left it has square root of 109 :frown:
for question 1b how many marks would be lost for integrating with limits 0 and 3.
Original post by Rgrewall
Didnt it say "in the third second" hence implying the integral had limits 4,3

No, third second implies between t=2 and t=3
Original post by Lilylollydove7
Did anyone else get 1.22 as their distance for the centre of mass?


Wasn't it from O, as you're removing the triangle, it'd be larger than 3sqrt(2)/2
because it shifts closer to the shape you have left.
Original post by linaxq
cant remember if i did 10.44 or 10.4 i might of left it has square root of 109 :frown:


Well it really depend on the examiner and ms. If you lucky its still correct so, only 1 mark gone its fine :smile:
Original post by Jakester11
How do you find lambda?


suvat

horizontal: s=lambda
vertixcal: s=-lamda

Fill in the other knowns, find t in terms of lambda using the horizontal (t=1/3 lambda) and then solve substituting this into s=ut+1/2 at^2 with the vertical values
Original post by Jakester11
How do you find lambda?


Equal the x distance to the negative of the y distance, solver for T, sub T back in to one of them.
Reply 392
Avatar for linaxq
linaxq
2
Original post by cjlh
73.3 was right -- that's 3sf.

Which question was 10.44? You may only lose 1 mark if it involved g


The calculation was square root of (10^2 + 3^2) to get square root 109 which iwas 10.44 and so on.

To get 10 i had to use g but to find 10.44 was a matter of pythagoras
Original post by kingaaran
Yeah I got this too - you're right :smile:


I did that too but it's actually wrong... 3rd second is from 2 to 3
Original post by Khoinet
Well it really depend on the examiner and ms. If you lucky its still correct so, only 1 mark gone its fine :smile:


When using gravity, they always penalise for 4SF or more.
Reply 395
Avatar for linaxq
linaxq
2
Original post by Major-fury
for question 1b how many marks would be lost for integrating with limits 0 and 3.


i want to know this too
Original post by linaxq
The calculation was square root of (10^2 + 3^2) to get square root 109 which iwas 10.44 and so on.

To get 10 i had to use g but to find 10.44 was a matter of pythagoras


Ohh yeah I see. That could go either way to be honest. Bit better than me, I forgot to square root 109 hahaha
Original post by Nesquickforce
No, third second implies between t=2 and t=3


How many marks do you think I'd get for putting in the wrong limits? 3 and 4 (it was 5 marks)
Original post by Major-fury
for question 1b how many marks would be lost for integrating with limits 0 and 3.


The question was 6 mars so I 'd say you got 3 and lost 3.
Original post by linaxq
not sure.
when i intergrated between 3-0 i got 15m i knew that the wording was off but ugh


Yeah I got exactly 15 too! Wonder what I did wrong..

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