The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

C3 Solomon H

Can anyone help? Question 4b).

maths.png

In the mark scheme they got that at (pi/2, -1), -1 = a+b.

And at (3pi/2, -5), -5 = a-b.

But I just don't understand why they got that... I know it's to do with -1 shifting the graph downwards, and b stretching the graph by a scale factor of b...

Thanks
(edited 7 years ago)
Original post by Barryl
Can anyone help? Question 4b).

maths.png

In the mark scheme they got that at (pi/2, -1), -1 = a+b.

And at (3pi/2, -5), -5 = a-b.

But I just don't understand why they got that... I know it's to do with -1 shifting the graph downwards, and b stretching the graph by a scale factor of b...

Thanks


Well, what is f:x actually? It's not to do with transformations or anything (it could be, but I could see that being more complicated than the alternative method).

Think about all of the information that you are given.
Original post by SeanFM
Well, what is f:x actually? It's not to do with transformations or anything (it could be, but I could see that being more complicated than the alternative method).

Think about all of the information that you are given.


Wow, can't believe I missed it. When x = pi/2, csc x = 1. So at (pi/2, -1), a+b(1) = -1

And at (3pi/2, -5), -5 = a + b(-1) = a-b.

Just had to think a little bit more...

Thanks for the push!
Original post by Barryl
Wow, can't believe I missed it. When x = pi/2, csc x = 1. So at (pi/2, -1), a+b(1) = -1

And at (3pi/2, -5), -5 = a + b(-1) = a-b.

Just had to think a little bit more...

Thanks for the push!


No worries. In any maths exam, or indeed any exam. think about the information you're given and what use it could possibly be.

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you