Could anyone help please - I'm stuck on question 4 of the unit 4 paper here: http://qualifications.pearson.com/content/dam/pdf/A%20Level/Physics/2013/Specification%20and%20sample%20assessments/sam-gce-physics.pdf The question's buried fairly deep so I'll try to explain: There are four graphs shown and the question asks which shows the relationship between Ywhen it is the electric field strength between two parallel plateswith a constant potential difference across them and X is thedistance apart of the plates? I thought it would be a straight line graph with a negative gradient but the answers show that it's D, a graph of exponential decay. I understand that Y should never become 0, but can't work out why it's an exponential graph because there are no powers in E=V/d?
Could anyone help please - I'm stuck on question 4 of the unit 4 paper here: http://qualifications.pearson.com/content/dam/pdf/A%20Level/Physics/2013/Specification%20and%20sample%20assessments/sam-gce-physics.pdf The question's buried fairly deep so I'll try to explain: There are four graphs shown and the question asks which shows the relationship between Ywhen it is the electric field strength between two parallel plateswith a constant potential difference across them and X is thedistance apart of the plates? I thought it would be a straight line graph with a negative gradient but the answers show that it's D, a graph of exponential decay. I understand that Y should never become 0, but can't work out why it's an exponential graph because there are no powers in E=V/d?
Thanks!
That's not an exponential graph, that's an inverse/reciprocal graph. If you look at a graph of y = 1/x you'll see :
Could anyone help please - I'm stuck on question 4 of the unit 4 paper here: http://qualifications.pearson.com/content/dam/pdf/A%20Level/Physics/2013/Specification%20and%20sample%20assessments/sam-gce-physics.pdf The question's buried fairly deep so I'll try to explain: There are four graphs shown and the question asks which shows the relationship betweenYwhen it is the electric field strength between two parallel plateswith a constant potential difference across them and X is thedistance apart of the plates? I thought it would be a straight line graph with a negative gradient but the answers show that it's D, a graph of exponential decay. I understand that Y should never become 0, but can't work out why it's an exponential graph because there are no powers in E=V/d?
Thanks!
D is not an exponential decay graph, it's a y=1/x graph which is correct because as you say E=V/d where V is constant, therefore Y=c/X where Y is E, d is X and c is a constant.
D is not an exponential decay graph, it's a y=1/x graph which is correct because as you say E=V/d where V is constant, therefore Y=c/X where Y is E, d is X and c is a constant.
Could anyone help please - For question 15bii) same paper as above, (page 58), how has the original value of current been calculated? The mark scheme uses a value of 1.6V but I can't see where that has come from? Sorry - I'm sure I'm asking really obvious questions
Could anyone help please - For question 15bii) same paper as above, (page 58), how has the original value of current been calculated? The mark scheme uses a value of 1.6V but I can't see where that has come from? Sorry - I'm sure I'm asking really obvious questions
Edit:
Oops - didn't see your post, I've asked the same!
I got an initial value of 0.75 A, but apparently thats wrong and I'm not sure why either
I got an initial value of 0.75 A, but apparently thats wrong and I'm not sure why either
That's what I got too - perhaps there's a mistake in the mark scheme? Sample assessments are prone to errors sometimes.
Also - did I see you're going to the UEA? That's one of my choices too. Would be nice to know someone there! My brother's just finished his degree there and loved it
That's what I got too - perhaps there's a mistake in the mark scheme? Sample assessments are prone to errors sometimes.
Also - did I see you're going to the UEA? That's one of my choices too. Would be nice to know someone there! My brother's just finished his degree there and loved it
I assume that its a mistake because I do not understand why they would use 1.6 v
Yes I am trying to get into UEA, it looks like a great uni to go to! Good to hear that your brother likes it too. What course are you thinking of doing there?
For 1 the charged particle experiences an electrostatic force of attraction and an electrostatic force of repulsion, which both act in the same direction so they don't cancel out at x. If both of the charges Q were the same, then the resultant force at x would be 0 because the forces would act in opposite directions.
I don't know if the resultant will be a maximum or minimum though
For 1 the charged particle experiences an electrostatic force of attraction and an electrostatic force of repulsion, which both act in the same direction so they don't cancel out at x. If both of the charges Q were the same, then the resultant force at x would be 0 because the forces would act in opposite directions.
I don't know if the resultant will be a maximum or minimum though
I assume that its a mistake because I do not understand why they would use 1.6 v
Yes I am trying to get into UEA, it looks like a great uni to go to! Good to hear that your brother likes it too. What course are you thinking of doing there?
English lit - the course looks great and really versatile! Did you apply for maths?