New Gcse Hard Maths Question

I'm struggling with question 3 on the new gcse maths paper. I got the answer 125/4, could anyone please check to see if it is right and if it isn't could you explain how to work it out. This type of question is a level 9(A**) in the new gcse.

Grade 9 Paper1.pdf851.3KB

Reply 1

leafcannon

Original post by theBranicAc

I got 6.25 instead of 125/4.

To get point D, substitute 0 in place of x. This makes y = 5, so point D is (0,5). To get point A, make substitute 0 in place of y. This leaves you with 0 = -2x + 5 , which gives x = 2.5. So the coordinates of A are (2.5,0).

Line (P)AB is perpendicular to line AD, so the gradient of AB must be -1/-2 , which is 1/2. The difference between the x coordinates point P (0,y) and point A (2.5,0) is 2.5. The change in y can be found by multiplying the change in x (2.5) by the gradient (0.5), which gives 1.25. Subtract this from the y coordinate of A (0), to get the the y value of P, -1.25. So the coordinates of P are (0,-1.25).

From this point, just work out the difference between the y coordinates (as the x coordinates just give 0), which is 6.25.

Reply 2

theBranicAc

Original post by leafcannon

ohh okay i seee cheers! :smile:

Reply 3

leafcannon

Original post by theBranicAc

ohh okay i seee cheers! :smile:

I actually did this before and I think I might've got 6.25 as well, but looking back on it, while it looks pretty solid I'm still not entirely sure.

It looks so fun!

Original post by leafcannon

I actually did this before and I think I might've got 6.25 as well, but looking back on it, while it looks pretty solid I'm still not entirely sure.

how would you express 0.213 with the repeating digits of 13 as fraction, question 10

(edited 7 years ago)

Reply 6

1jonam16

Original post by theBranicAc

Wait, these are the new hard questions? I thought they were making GCSEs harder, it seems these are just normal questions youd find at the end of a paper, it makes no sense to change the grading systems aif the standard is the same, the only difference is that you guys get a free double A* for doing the same Questions as us.

Reply 7

theBranicAc

Original post by 1jonam16

you may not find it hard, but theres harder questions than that if you think it was easy

what did you get for question 16?

Reply 8

ituneserror

Original post by theBranicAc

you may not find it hard, but theres harder questions than that if you think it was easy

what did you get for question 16?

Spoiler

Reply 9

theBranicAc

Original post by ituneserror

Spoiler

how did you work it out may i ask?

Reply 10

ituneserror

Original post by theBranicAc

how did you work it out may i ask?

38 Degrees = Angle BAE = Angle DBA because alternate angles are equal ('z' angles).

Angles in a triangle add up to 180 and the base angles of an isosceles triangle are equal, so Angle DAB plus Angle CBA plus Angle ADB is 180 Degrees. And we know that Angle DBA is 38, so 38x2= 76. 180-76=104 Degrees.

We also know that Triangles ADB and CDB are equal becuase they share two equal sides and the same angle so they must be equal (SAS). This means that Angle ADB = Angle CDB = 104 Degrees. And we know that an angle by itself adds up to 360 Degrees. This means that Angle ADB plus Angle CDB plus Angle ADC is 360. 360-(104x2)= 152 Degrees. So x = 152 Degrees. :smile:

Reply 11

leafcannon

Original post by theBranicAc

how would you express 0.213 with the repeating digits of 13 as fraction, question 10

Take 0.2 (2/10) away from 0.213... , leaving 0.013... . Label this x. Times that by 1000 to get 13.13... or 1000x. Subtract 10x from this to get exactly 13, or 990x.

This leaves x = 13/990. Add the 2 tenths (198/990) you originally took away to yield the answer, 211/990.