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https://07a69ccf283966549a9350d1a66951a7bc96e2dc.googledrive.com/host/0B1ZiqBksUHNYZ0JQM1NRcmdHdXM/January%202014%20(IAL)%20QP%20-%20C3%20Edexcel.pdf

Question 8a. I get that I have to work out the range of the function first in order to get the domain of the inverse.

How would I find the range? I draw it out and the y cooerdinate is (0,1) but range seems to be < 3??
Original post by imran_
https://07a69ccf283966549a9350d1a66951a7bc96e2dc.googledrive.com/host/0B1ZiqBksUHNYZ0JQM1NRcmdHdXM/January%202014%20(IAL)%20QP%20-%20C3%20Edexcel.pdf

Question 8a. I get that I have to work out the range of the function first in order to get the domain of the inverse.

How would I find the range? I draw it out and the y cooerdinate is (0,1) but range seems to be < 3??


draw out the f(x) graph and you will see there is an assymptote at y=3, hence the range of f(x) is f(x) < 3

we can then deduce the domain of the inverse function from this
(edited 7 years ago)
Reply 2
Original post by Katiee224
draw out the f(x) graph and you will see there is an assymptote at y=3, hence the range of f(x) is f(x) < 3

we can then deduce the domain of the inverse function from this


i did draw it several times im still getting wrong? mind showing me a worked solution
Original post by imran_
i did draw it several times im still getting wrong? mind showing me a worked solution


does this help :smile:
Reply 4
Original post by Katiee224
does this help :smile:


i got the same shape but the Y cooerdiante is 1?
Original post by imran_
i got the same shape but the Y cooerdiante is 1?


yes that's right, it crosses the y axis at 1 and the x axis at -1

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