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Edexcel Physics U4 IAL (WPH04/1)

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Reply 20

skeletonboy1

do we have to use area to calculate charge when calculating the capacitance in the second last question?

Reply 21

Zacken

Original post by skeletonboy1

yeah as i remember, and we only need to resolve when calculating velocities but no need when calculating K.E. right?

Yep.

Reply 22

AvWOW

Original post by omar5478

I got 3.41, I believe I calculated it by (6.9 - 6cos30)/cos60 (total horizental momentum before = total horizental momentum after)

Ah yes. That's what I did! I guess I must have gotten the same, just can't remember it

Reply 23

omar5478

Original post by AvWOW

yup I did the same.
haha everyone was saying they remembered it from IGCSE and I was like "what really"

Oh ffs that actually makes sense. I guess I could say goodbye to the A*

Reply 24

Zacken

Original post by omar5478

The only irritating question was the change of momentum of the alpha particle, how did you do that ??

I've forgotten the question, but I think it had something to do with E_k = p^2/(2m) or something along those lines.

Reply 25

AvWOW

Original post by omar5478

Oh ffs that actually makes sense. I guess I could say goodbye to the A*

Hey that was just 3 marks.. I'm prob losing more than that

Reply 26

skeletonboy1

Original post by Zacken

I've forgotten the question, but I think it had something to do with E_k = p^2/(2m) or something along those lines.

yeah i used that equation too but i used a mass of 2u instead of 4u fml

Reply 27

AvWOW

Original post by skeletonboy1

do we have to use area to calculate charge when calculating the capacitance in the second last question?

Yeah I did

Reply 28

omar5478

Original post by Zacken

I've forgotten the question, but I think it had something to do with E_k = p^2/(2m) or something along those lines.

I did that to calculate the initial momentum (7.8 * 10^something) but didn't know how to progress beyond that.

Edit: I just figured out that this value would be the change of momentum because at minimum seperation there would be no velocity. I didn't write that down though and wrote F = p/t below the calculation, do you know how many marks would I lose ??

(edited 7 years ago)

Reply 29

oli4rg

Original post by Zacken

I've forgotten the question, but I think it had something to do with E_k = p^2/(2m) or something along those lines.

A question very similar came up in January 2016
Question 18 C

Papers and Markschemes
https://drive.google.com/folderview?id=0B1ZiqBksUHNYRGN5em5NNENweE0&usp=drive_web&tid=0B1ZiqBksUHNYUnR2ZW5PcGhLQWM

Reply 30

skeletonboy1

for the mc questions:
deflection is higher or lower?
momentum change = sqrt(2)p?

Reply 31

Zacken

Original post by omar5478

I did that to calculate the initial momentum but didn't know how to progress beyond that.

You'll get a mark at least.

Reply 32

AvWOW

I think I messed up the question about the wavelength. I used E=hf and then c=f(lamda) which I think could be right...
But then I confused getting Ek. How was that supposed to be done?

Reply 33

Zacken

Original post by oli4rg

A question very similar came up in January 2016
Question 18 C)
https://drive.google.com/folderview?id=0B1ZiqBksUHNYRGN5em5NNENweE0&usp=drive_web&tid=0B1ZiqBksUHNYUnR2ZW5PcGhLQWM

Markscheme
https://drive.google.com/folderview?id=0B1ZiqBksUHNYRGN5em5NNENweE0&usp=drive_web&tid=0B1ZiqBksUHNYUnR2ZW5PcGhLQWM

Yep, Q16 also came up as Q11 in ours. Q15 came up in ours as well. It's basically the same paper with different numbers.

Original post by skeletonboy1

for the mc questions:
deflection is higher or lower?
momentum change = sqrt(2)p?

Dunno what the deflection bit you're talking about is. Are you talking about the last question about exiting the field? If so, it exits at C.

Momentum change = 2p.