Correct me if I'm wrong. The gaps are for answers I don't remember or questions.
1. 3x^2 - 20x [3] 2. a = 3, b = -20 [3] 3. (a) 12th term [2] (b) 3/5 limiting factor [1] 4. (a)-5, 8 - basically it was opposite the numbers in the brackets [1] (b) root 10 - radius [1] 5. Prove the two line segments were perpendicular. AB gradient = -10/4 and BC gradients = 4/10, multiply the two gradients to get -1 so they are perpendicular.[3] 6. m = 8, p = -1 [4] 7. 9, 10, 11 [3] 8. x = 121 [3] 9. x^3 - 15x^2 + 75x - 125 [3] 10. -80, x = 16 and y = -1/5 [4] Should be 11. Circle theorem: 180 - 3x 2x + 58 = 2(180 - 3x) 2x + 48 = 360 - 6x 8x = 312 x = 39 [3] 12. (a) h = 3, k = -7 [2] (b) -3, -7 [1] (c) -3 +/- root 7 [1] 13. sqrt(125) + sqrt(20) = sqrt(80) + sqrt(x). Answer: x = 45 [3] 14. (a) When 3 is put into equation and a is 1, the equation is equal to 0. [2] (x-3)(x-7)(x+2) - use long division first to get quadratic then factorise it [3] 15. 2root7 - 4 [3] 16. -5/6 for the cos and sine question [4] 17. k = 9 [5] 18. What Q? x^4 - 81 (I think it was this) = (x^2 + 9)(x+3)(x-3) [I think 2 marks] 19. (a) Use pythagoras theorem, 9 + 9 = 18, side = root 18 = 3 root 2 [2] (b) Trapezium - Idk, but I got the answer somehow: the bottom side of the triangle was root 3 and the hypotenuse was 2root3. Add it all together: 3 + 3 + 3 + 2 root 3 + root 3 = 9 + 3 root 3, thats what u get when u expanded what they gave so it's correct. [4] 20. Cosine rule. Cos P = 1/3. Use the rule, you find u have to do 4/12 to get 1/3. So, you do 13n^2 - 4n^2 = 9n^2 That's w^2 so w = 3n. w = 3n same as the other side, so the triangle is isoceles. [4]
Well, I thought I had got really low, but after checking it again, it seems way better!
Correct me if I'm wrong. The gaps are for answers I don't remember or questions.
3x^2 - 20x
12th term 3/5 limiting factor
-5, 8 - basically it was opposite the numbers in the brackets Root 10? - radius
m = 8, p = -1 8 < x < 12
x = -55 x^3 - 15x^2 + 75x - 125 80, x = 16 and y = 1/5
h = 3, k = -7 -3, -7 -3 +/- root 7
x = 45 When 3 is put into equation and a is 1, the equation is equal to 0. (x-3)(x-7)(x+2) - use long division first to get quadratic then factorise it
2root7 - 4 5/6 or -5/6 ?
k = 9 apparently ( i missed it out)
Use pythagoras theorem, 9 + 9 = 18, side = root 18 = 3 root 2 Trapezium - Idk, but I got the answer somehow: the bottom side of the triangle was root 3 and the hypotenuse was 2root3. Add it all together: 3 + 3 + 3 + 2 root 3 + root 3 = 9 + 3 root 3, thats what u get when u expanded what they gave so it's correct. x^4 - 81 (I think it was this) = (x^2 + 9)(x+3)(x-3) Cosine rule. Cos P = 1/3. Use the rule, you find u have to do 4/12 to get 1/3. So, you do 13n^2 - 4n^2 = 9n^2 That's w^2 so w = 3n. w = 3n same as the other side, so the triangle is isoceles.
1.) Is right 2.) Was the matrices question a=3 b= -20 ( if i remember correctly) 3.) Nth term is correct cirlce question is correct 39 degrees is the answer to the circle theorem question 8<x < 12 is correct For the x/y question y= -1/5 as it has to be less than 0 So the answer is -80 Completing square is correct Surds is correct Factor theorem is correct -5/6 is the correct for the cos theta question K = 9 is correct Trapezium question is solved using the 30,60 triangle and the 45,45 triangle . The diagnol side is 2 root 3 and the bottom is root 3 Factorising is correct Isosceles proof is correct but i did it a different way
1.) Is right 2.) Was the matrices question a=3 b= -20 ( if i remember correctly) 3.) Nth term is correct cirlce question is correct 39 degrees is the answer to the circle theorem question 8<x < 12 is correct For the x/y question y= -1/5 as it has to be less than 0 So the answer is -80 Completing square is correct Surds is correct Factor theorem is correct -5/6 is the correct for the cos theta question K = 9 is correct Trapezium question is solved using the 30,60 triangle and the 45,45 triangle . The diagnol side is 2 root 3 and the bottom is root 3 Factorising is correct Isosceles proof is correct but i did it a different way
This is what happens when I rush and don't read questions and skip the information ffs. x = -55 is right isn't it - the one with the bracket and to the power of 1/3 or something.
There was a question related to completing the square in a quadratic equation and you were meant to answer in the form (a+-sqrt.b). What if you solved it by using the quadratic formula
With the question 8<x<12 apparently it asked for the integer values that x could be, i.e. 9,10,11 I put 8<x<12 but others said it asked for integers :/
With the question 8<x<12 apparently it asked for the integer values that x could be, i.e. 9,10,11 I put 8<x<12 but others said it asked for integers :/
That's okay. It's the same. 8<x<12 is actually cool. Not used by anyone on the street.
There was a question related to completing the square in a quadratic equation and you were meant to answer in the form (a+-sqrt.b). What if you solved it by using the quadratic formula
Correct me if I'm wrong. The gaps are for answers I don't remember or questions.
3x^2 - 20x a = 3, b = -20 12th term 3/5 limiting factor
-5, 8 - basically it was opposite the numbers in the brackets Root 10 - radius
m = 8, p = -1 8 < x < 12
x = -55 x^3 - 15x^2 + 75x - 125 -80, x = 16 and y = -1/5
h = 3, k = -7 -3, -7 -3 +/- root 7 Circle theorem: 180 - 3x 2x + 58 = 2(180 - 3x) 2x + 48 = 360 - 6x 8x = 312 x = 39 Another question: x = 45 When 3 is put into equation and a is 1, the equation is equal to 0. (x-3)(x-7)(x+2) - use long division first to get quadratic then factorise it
2root7 - 4 5/6 for the cos and sine question?
k = 9
Use pythagoras theorem, 9 + 9 = 18, side = root 18 = 3 root 2 Trapezium - Idk, but I got the answer somehow: the bottom side of the triangle was root 3 and the hypotenuse was 2root3. Add it all together: 3 + 3 + 3 + 2 root 3 + root 3 = 9 + 3 root 3, thats what u get when u expanded what they gave so it's correct. x^4 - 81 (I think it was this) = (x^2 + 9)(x+3)(x-3) Cosine rule. Cos P = 1/3. Use the rule, you find u have to do 4/12 to get 1/3. So, you do 13n^2 - 4n^2 = 9n^2 That's w^2 so w = 3n. w = 3n same as the other side, so the triangle is isoceles.
For the inequality, t asked for integer solutions. Wouldn't you therefore have had to put 9, 10 and 11? Other than that and question 6 (which I knew I'd completely messed up) I think I've done very well
Can someone explain the limiting factor one and how it was 3/5? I though it was 2.4 cos then the denominator would equal 0 and the fraction would be undefined