H2O2 + 2e– 2OH–
2[Cr(OH)6]3–+ 3H2O2 2CrO42–+ 8H2O + 2OH–
can someone please explain how they got the overall balanced equation? its from question 7b ii in jan 2011 paper
does anyone know what the half equatoin for the oxidation of [Cr(OH)6] to 2CrO4 would be in order to get the above overall equation as im struggling to come up with a balanced one
thanks