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AQA MM1B - Mechanics 1 -Tuesday 21st June 2016

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Original post by GabbytheGreek_48
think i also got 1.12


I definitely got 1.12 as well

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Original post by wil_is_he
I can do some if it... Hopeully others wilk fill in after.

2 helicopters A and B,
A is at origin, B is at position (maybe 50i 40j? Someone needs to help)
A has acceleration (-0.2i + 0.1j), B: (0.2i - 0.1j)
Cant remember inial velocity...
Q: What is the distance A to B when their velocities are parallel. Answer=106. If others could fill in gaps thatll help. You can either do c4 method or gradient method, t=12


Everything you put is right. Initial velocity of B was (6i + 9j). Cant remember A
Original post by Peter Wilkinson
Did no one get around 07.6 for the bearing ? :|


Bearing was 008 so ye think so
Original post by LiesandAlibis
R = Tsin(6) +49

How
Original post by OturuDansay
for question 7, was the horizontal velocity 12cos50 or something, I can't remember what the initial figures were when setting up the question. Someone help lol


horizontal a=0
u=12cos(50)
t=1.76(from previous answer)
s= what your finding
Original post by jdtjCdiifn
Everything you put is right. Initial velocity of B was (6i + 9j). Cant remember A


A was 4i and can't remember the j
Original post by gcsekid
image.jpg
Ignore the pencil line
How are people getting 43 newtons for T


R=49+Tsin60 not R+Tsin60=49 I think

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Original post by gcsekid
How


The vertical component of T acts downwards along with weight.
Original post by PiTheta97
I definitely got 1.12 as well

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uh i must of typed in something wrong, i put v=0
Original post by gcsekid
How


think he means 60 instead of 6 and 49 = 5g (5*9.8)
Original post by koolgurl14
:frown: 10 more marks gone


Sorry. :frown:
Original post by LiesandAlibis
The vertical component of T acts downwards along with weight.

What would I lose for that then how many marks for the minus sogn
Original post by GabbytheGreek_48
horizontal a=0
u=12cos(50)
t=1.76(from previous answer)
s= what your finding


Could you tell me how you got 1.76 because I got like 1.18 seconds or somit and just wanna see ur method if that's alright :smile:
Original post by Ano123
Sorry. :frown:


think the grade boundaries will probably b low because thw whole 10 marks for one question and easy to lose marks some places
Original post by matt5822
Full as long as you got the distance to be 106 m.


i found the distance of each and found the difference between distances rather than finding difference between the displacements and then finding distance :frown:
Original post by OturuDansay
for question 7, was the horizontal velocity 12cos50 or something, I can't remember what the initial figures were when setting up the question. Someone help lol

The horizintal velocity to the start of the box was 12cos50 yes
its not R+tsine60=5g. its R=5g-Tsin60. the vertical component of tension acts against the reaction therefore its pushing the block towards the ground, not lifting it up as you have suggested.
Original post by gcsekid
image.jpg
Ignore the pencil line
How are people getting 43 newtons for T
Original post by GabbytheGreek_48
think he means 60 instead of 6 and 49 = 5g (5*9.8)


Yes, that was a typo!
Original post by OturuDansay
Could you tell me how you got 1.76 because I got like 1.18 seconds or somit and just wanna see ur method if that's alright :smile:


idr but i think i resolved vertically so vertical was
s=1
u=12sin(50)
a=-9.8
t=what your finding
you put those in and eventually get a quadratic do quadratic formula and then i used the higher value
Original post by postexamtalk
i found the distance of each and found the difference between distances rather than finding difference between the displacements and then finding distance :frown:


You should still get most of the marks. I think the hardest part was finding the value of t.

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