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maths help

Could someone please help me on this question?

m:n=3:8 and r is 20% of n.
work out m:r.
I keep getting 3:40 but it's wrong :frown:
Original post by penelopecrux
Could someone please help me on this question?

m:n=3:8 and r is 20% of n.
work out m:r.
I keep getting 3:40 but it's wrong :frown:


To start with what's r:n ?
Original post by ghostwalker
To start with what's r:n ?


i think it's r:n = 1:0.2
Original post by penelopecrux
i think it's r:n = 1:0.2


Not quite.

Well r is 20% of n, so 1 r will go with 5 n, hence r: n is?
n = 20% of r

is useful
Original post by ghostwalker
Not quite.

Well r is 20% of n, so 1 r will go with 5 n, hence r: n is?



it's 5:1 YESSS I'VE GOT IT!! Thank you so much, the answer's 15:8. Is it also possible if you could help me on another question please?? :smile:
Original post by penelopecrux
it's 5:1 YESSS I'VE GOT IT!! Thank you so much, the answer's 15:8. Is it also possible if you could help me on another question please?? :smile:


I'm not convinced you've understood, though could by wrong, but for the benefit of other users, here's some working. Please check though.

r is 20% of n, so for every 20 r we have 100 n, and dividing through we have 1 r to 5n.

So, r:n is 1:5

and it follos that n:r is 5:1

Now m:n is 3:8.

We need the ratio of the n's to be the same in order to combine the ratios.

So, multiplying n:r as 5:1 by 8, we have n:r is 40:8

Multiplying m:n as 3:8 by 5, we have m:n is 15:40

Now we have the same ratio for n in both and can combine them.

m:n:r = 15:40:8, and hence m:r = 15:8

Apologies if that was obvious to you now.

What's your other question?
(edited 7 years ago)
Original post by ghostwalker
I'm not convinced you've understood, though could by wrong, but for the benefit of other users, here's some working. Please check though.

r is 20% of n, so for every 20 r we have 100 n, and dividing through we have 1 r to 5n.

So, r:n is 1:5

and it follos that n:r is 5:1

Now m:n is 3:8.

We need the ratio of the n's to be the same in order to combine the ratios.

So, multiplying n:r as 5:1 by 8, we have n:r is 40:8

Multiplying m:n as 3:8 by 5, we have m:n is 15:40

Now we have the same ratio for n in both and can combine them.

m:n:r = 15:40:8, and hence m:r = 15:8

Apologies if that was obvious to you now.

What's your other question?


Thanks so much for this.
my other question is:
a:b = 2:3
write a in terms of b
Original post by penelopecrux
Thanks so much for this.
my other question is:
a:b = 2:3
write a in terms of b


What are your thoughts? Can you write it as a percentage?
Original post by ghostwalker
What are your thoughts? Can you write it as a percentage?


i think it's a= 3/5b
Original post by penelopecrux
i think it's a= 3/5b


a:b :: 2:3 means for every 2 a there are 3 b

So, for every a, there are 3/2 b

hence a=2/3 b

Notice that the fraction has inverted.
Original post by ghostwalker
a:b :: 2:3 means for every 2 a there are 3 b

So, for every a, there are 3/2 b

hence a=2/3 b

Notice that the fraction has inverted.


wait why does the fraction invert???
Original post by penelopecrux
wait why does the fraction invert???


2:3 ::a:b

Putting it another way

If you have 2 a then you have 3 b

So if you have 2/3 a then you have 1 b

So for every b, there is 2/3a, i.e. the number of a's is 2/3b, i.e. a=2/3 b

This is the sort of thing that should be covered in your textbook.
Original post by ghostwalker
2:3 ::a:b

Putting it another way

If you have 2 a then you have 3 b

So if you have 2/3 a then you have 1 b

So for every b, there is 2/3a, i.e. the number of a's is 2/3b, i.e. a=2/3 b

This is the sort of thing that should be covered in your textbook.


yeah but you know how it's 2/3a=b and you make a the subject wouldn't it be 1b/2/3 which is 3/2b?
Original post by penelopecrux
yeah but you know how it's 2/3a=b and you make a the subject wouldn't it be 1b/2/3 which is 3/2b?


But it's not 2/3 a= b

Perhaps it would be elearer with a different example, suppose it's a:b :: 1:10

So, for every a there are 10 b's

So, the number of b's is 10 times the number of a's, i.e. b=10a, and

a = 1/10 b
Original post by ghostwalker
But it's not 2/3 a= b

Perhaps it would be elearer with a different example, suppose it's a:b :: 1:10

So, for every a there are 10 b's

So, the number of b's is 10 times the number of a's, i.e. b=10a, and

a = 1/10 b


see, i understand your example and im applying it to the previous question but I'm still getting a=3/2 b because the number of b's is 3/2 times the number of a's
Original post by penelopecrux
see, i understand your example and im applying it to the previous question but I'm still getting a=3/2 b because the number of b's is 3/2 times the number of a's


If the number of b's is 3/2 times the number of a's, then the number of a's is 2/3 times the number of b's, and a=2/3b
Original post by ghostwalker
If the number of b's is 3/2 times the number of a's, then the number of a's is 2/3 times the number of b's, and a=2/3b


yep i thought about it, i get it now thank you :tongue:
Easiest way to do this is to convert ratios to fractions.

m:n=3:8m:n=3:8 so mn=38\dfrac{m}{n}=\dfrac{3}{8}.

r=15nr=\dfrac{1}{5}n, so mr=m15n=5mn\dfrac{m}{r}=\dfrac{m}{\frac{1}{5}n}=\dfrac{5m}{n}

So m:r=5m:n=15:8m:r=5m:n=15:8.

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