fp2 help

http://mathsathawthorn.pbworks.com/f/FP2+JUNE+2009.pdf
Can someone help me to do 8d? Like i dont know how to do it:/

I haven't done inverse of rational functions before but by investinging it I think I can help.

The question is asking for the values of $y$ will the inverse function be between $0<x<10$. This means that for the original function, the opposite is true; for which values of $x$ will the function be between $0<y<10$. If you were to find solutions to $f(x)=0$ and $f(x)=10$, and by looking at the graph you sketched you should notice that the solutions are bounds of intervals. One being $-3<x<0$ and the other $2<x<5$ which should be the solutions to the question once you consider the inverse.

As I said, I haven't covered this topic so I'm not an expert as it does not appear on any of my modules (FP2 included, from AQA) + the inverse function confusion doesn't help, but hopefully it gets you going in the right direction. If you need to, use graphing software like Desmos to see what I mean. The function $f^{-1}(x)=(+/-)[(1/4)(3-x)^{2} - x]^{1/2} - (1/2)(3-x)$