OCR MEI FP2 Thread - AM 27th June 2016

Original post by aproei

What is the w³+w²+ w = 0 thing?

[video]https://youtu.be/WlM1WjmAkA0?t=14m53s[/video]

Maybe I should've written w² + w + 1 = 0 instead.

Reply 82

aproei

Original post by Wunderbarr

[video]https://youtu.be/WlM1WjmAkA0?t=14m53s[/video]

Maybe I should've written w² + w + 1 = 0 instead.

Gotcha

Reply 83

anyone help on jan 06 4Cii? dont understand what to do after I intergrated by parts

Posted from TSR Mobile

Reply 84

Original post by HFancy1997

anyone help on jan 06 4Cii? dont understand what to do after I intergrated by parts

Posted from TSR Mobile

You get to the necessary result, then realise you need to change the 2arsinh(4/3) -1 into a natural log somehow...

So, look in the formula booklet. Page 2, bottom right corner.

Reply 85

Original post by Wunderbarr

You get to the necessary result, then realise you need to change the 2arsinh(4/3) -1 into a natural log somehow...

So, look in the formula booklet. Page 2, bottom right corner.

Sorry I shouldve been more clear,

I got uv but dunno what to do with the -intergral(Vdu/dx), I just dont see how went to the next step

Posted from TSR Mobile

Reply 86

Original post by HFancy1997

Sorry I shouldve been more clear,

I got uv but dunno what to do with the -intergral(Vdu/dx), I just dont see how went to the next step

Posted from TSR Mobile

Rewrite the integral as brackets and powers (so no fractions or square roots).

You should be able to tell what type of integration is done more clearly.

The rewritten integral should appear something like:

Spoiler

Reply 87

Original post by Wunderbarr

Rewrite the integral as brackets and powers (so no fractions or square roots).

You should be able to tell what type of integration is done more clearly.

The rewritten integral should appear something like:

Spoiler

damn man, I still dont see it Lol? i wouldve done substitution again for that but isnt that too complicated?

Posted from TSR Mobile

Reply 88

Original post by HFancy1997

damn man, I still dont see it Lol? i wouldve done substitution again for that but isnt that too complicated?

Posted from TSR Mobile

It's a simple integration. Think about reversing the chain rule.

Reply 89

Original post by HFancy1997

damn man, I still dont see it Lol? i wouldve done substitution again for that but isnt that too complicated?

Posted from TSR Mobile

I'm going off now, and you should too soon!

Happy hunting tomorrow everyone!

Reply 90

Alex621

17

Original post by HFancy1997

damn man, I still dont see it Lol? i wouldve done substitution again for that but isnt that too complicated?

Posted from TSR Mobile

I just watched this video on the topic which helped but I think in the exam I will use substitution even though it takes longer.

https://www.youtube.com/watch?v=lvkz1fKlxwQ

Reply 91

Bunderwump

7

Could not finish off that last question. I always struggle with actual numbers and tedious expansions. Left my answer as a long string of (3+sqrt(5))^2 and such. Think I got everything else.

Reply 92

ComputerMaths97

17

Damn that was tough, two new styles of questions never done before too. Annoying though, forgot something very basic during the exam

Reply 93

last question you had to change sinh to exponentials then it gives you a surd numbee, not sure if its right but I did that

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Reply 94

Sophieoo1

Original post by Bunderwump

Could not finish off that last question. I always struggle with actual numbers and tedious expansions. Left my answer as a long string of (3+sqrt(5))^2 and such. Think I got everything else.

Yes me too I just ran out of time

Reply 95

19Beth97

1

I think tha exam is the hardest ive ever done. Im just praying on low grade boundaries or im kissing uni goodbye. How did everone else find it.

Reply 96

Sophieoo1

Someone do an unofficial markscheme plzz

Here are fragments from my memory:

For Q1 I remember getting pi/6 as the integration

Q2: in part (i) it simplified to 1 - z

root arguments were pi/18, 13pi/18, -11pi/18 and modulus was root 2

Q3: M-1^n tends to infinity

Q4: show that..
x = plus/ minus ln 3+root5 /2

curve had y intercept at 2 and was symmetrical for plus and minus x

Yh thats all I can remember atm and these are just my answers so may be wrong

Reply 97