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New Maths 9-1 GCSE Sample Question HELP NEEDED!

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So I was revising for my End Of Year exam which will be a mock of the REAL new GCSE and this question came up.
Anyone know , step by step, how to solve this?

Thanks
(edited 7 years ago)
Original post by NothingButWaleed
So I was revising for my End Of Year exam which will be a mock of the REAL new GCSE and this question came up.
Anyone know , step by step, how to solve this?


can't see the question :redface:
Original post by fatima1998
can't see the question :redface:


Its there now!
Reply 3
Draw line from A to C and one from A horizontally across to the line DC. You then get a right angled triangle and use the angle along with the ratio to get sides etc.
Work out the other side using the ratio.
Draw the angle of elevation and then draw a right angled triangle connecting the two lines together. You will realise the angle of elevation is the same as one of the angles - corresponding angles ? :smile:

Use SOH CAH to then work it out.
Well, in all honesty you can only use tan or TOA haha :smile:


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Original post by Chittesh14
Work out the other side using the ratio.
Draw the angle of elevation and then draw a right angled triangle connecting the two lines together. You will realise the angle of elevation is the same as one of the angles - corresponding angles ? :smile:

Use SOH CAH to then work it out.
Well, in all honesty you can only use tan or TOA haha :smile:


Posted from TSR Mobile


I just tried it but no luck. I do something wrong but I dont know what, can you do the working out and show me?
Reply 6
CD = 1.5 x 1.7 = 2.55

Let E be the point where a perpendicular line to AB, at A intersects CD

CE = CD - AB = 2.55 - 1.7 = 0.85

To work out EA use trig:

Tan(angle) = opp/adj
Tan(52) = (0.85)/EA
EA = (0.85)/tan(52)
EA = 0.6640927... = 0.664 (to 3sf)

EA = BD
Therefore BD = 0.664 (to 3sf)

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