OCR MEI FP2 Thread - AM 27th June 2016

My answers, by no means right, just want to compare with people :

1)i) 1 - x^2 + x^4

ii) x - 1/3 x^3 + 1/5 x^5

iii) pi/6

iv) Draw the graph, sort of like a loop but starting at pi/4 and ending on the horizontal axis

As the angles tends to 0 r tends to infinity

v) a^2 ln(2 root2) or 1/2 a^2 ln 8

2)i) 1-z

ii) Show that C + jS thing

iii) Modulus of the cube roots was root2 the angles were pi/18 13pi/18 25pi/18


3)i) Eigenvalues were -1/6, 1 eigenvectors were (1 1) and (3 -4) I think, cant quite remember the order

ii) M^n tended towards (3 4) or something like that order might be different
.................................(3 4)
cant quite remember

iii) Not too sure on this, I think it didnt tend to a limit (maybe infinity), as the elements of the matrix were greater than 1 but some were negative so it could have positive or negative infinity

4)i) Show that arcosh thing

ii) ln((3+root5)/2) and ln((3-root5)/2)

iii) The graph sort of looked like x^2 but started at y=2

The area bound by the curve was 5root5 / 2
The area bound by the line y = 5 was 5ln((7+3root5)/2)

Then take one away from the other.


I think that was all the questions, not sure how many are right, just what I got

Agree with all in Q1 and I think you have to show that +C = 0 - that counted as 2 marks in a past paper
Also I put that r tends to +/- infinity - is this ok???

Agree with Q2
Agree with Q3 but I got M^n tends to a matrix - can't remember but it had like 3/7 and 4/7 in it
For part 3 I just put tends to infnity so does not tend to a limit.

Q4; for the area I got 10ln (3+root5/2) - something ...

@decombatwombat I agree with almost everything (which is great ) except I argues that the area bound by y=5 was $5*2ln(\frac{3+\sqrt{5}}{2})$ and I can't see how you got your answer.

Any predictions for the A boundary?

Any predictions for the A boundary?

63/64?

I think I put the 2 inside, so that it was the thing in the ln squared, which equals the same as yours.

funny

63/64?

Any predictions for the A boundary?

Yeah that was probably a bit high of an estimate, its just that FP2 boundaries tend to be pretty high. Most likely it will be 59/60