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Equations containing fractions

Just wondering if anyone could explain how to solve-

2 - 5/x = 10/x - 1

I understand the jist of it but just wanted a second opinion on how to go about working it out :smile:
Reply 1
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1420787
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Multiply every term by the lowest common multiple of any denominators in the equation.

In this case, the denominators are 'x' and 'x'. LCM is 'x', so multiply by that.

Job's a good 'un.
Reply 2
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miaofcourse
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Original post by offhegoes
Multiply every term by the lowest common multiple of any denominators in the equation.

In this case, the denominators are 'x' and 'x'. LCM is 'x', so multiply by that.

Job's a good 'un.


Thank you!! So will I times the 2 by -1 as well??
I assume you mean 2−5x=10x−1 2-\frac{5}{x}=\frac{10}{x}-1? This just goes to 2x-5=10-x as you multiply everything by x.

For 2−5x=10x−1 2-\frac{5}{x}=\frac{10}{x-1} , just multiply both sides by x-1 and then again by x.
(edited 7 years ago)
Reply 4
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miaofcourse
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Original post by RDKGames
I assume you mean 2−5x=10x−1 2-\frac{5}{x}=\frac{10}{x}-1? This just goes to 2x-5=10-x as you multiply everything by x.


Ahh thank you, that what I wanted to clarify :smile:
Reply 5
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1420787
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Original post by miaofcourse
Thank you!! So will I times the 2 by -1 as well??


See the post below yours. Did you mean that equation? Or did you mean 10/(x-1)?

If it's the latter, then multiply by the LCM of x and (x-1), which is x(x-1).
Reply 6
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miaofcourse
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Original post by offhegoes
See the post below yours. Did you mean that equation? Or did you mean 10/(x-1)?

If it's the latter, then multiply by the LCM of x and (x-1), which is x(x-1).



I meant the one below my post, sorry for any confusion!
Original post by miaofcourse
I meant the one below my post, sorry for any confusion!


No problem! :smile:

Just in the future try to use brackets in order to avoid any confusion, fractions give us a million interpretations without them. :tongue:
(edited 7 years ago)

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