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why do i need both positive and negative values (completing the square)

(x+0.4)^2 = 4

(x+0.4) = ±2

x =1.6 or x = -2.4

i know that square rooting gives you negative and positive answer, but why, why ±??

another example is the quadratic equation where theres the ±
(edited 7 years ago)

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It doesn't. This is a common misconception.

http://www.thestudentroom.co.uk/showthread.php?t=3173187

All the best :h:
+/- basically means the result is both positive and negative of the number. You can write the answer as separated positive and negatives (e.g. 2 and -2 instead of +/-2).

Above pretty much said what else is needed.
(edited 7 years ago)
-2^2 = 4 , 2^2 = 4

therefore if your answer is √4, it could be any of those two values unless they specify x>0, etc...

Its easier to notate it ±2, than writing out the former.
Reply 4
This is asking "what number(s) do I need to add 0.4 to and then square the whole thing to get 4?".

So we break it down into steps:

1) what number(s) do I need to square to get 4

2) what number do I need to add 0.4 and then square to get 4.

So the first step, there are two numbers that square to give 4, that is: +2 or -2. We write these as ±2\pm 2, it's saying "2 or -2" are solutions to the equation y^2 = 4.
Reply 5
Original post by SeanFM
It doesn't. This is a common misconception.

http://www.thestudentroom.co.uk/showthread.php?t=3173187

All the best :h:



thanks! looking at these equations on graphs make my head dizzy but i'll get used to it. :redface:
You really didn't know that (-2)^2 and 2^2 = 4?

Posted from TSR Mobile
Reply 7
Original post by Vikingninja
+/- basically means the result is both positive and negative of the number. You can write the answer as separated positive and negatives (e.g. 2 and -2 instead of +/-2).

Above pretty much said what else is needed.


Original post by 34908seikj
-2^2 = 4 , 2^2 = 4

therefore if your answer is √4, it could be any of those two values unless they specify x>0, etc...

Its easier to notate it ±2, than writing out the former.


Original post by Zacken
This is asking "what number(s) do I need to add 0.4 to and then square the whole thing to get 4?".

So we break it down into steps:

1) what number(s) do I need to square to get 4

2) what number do I need to add 0.4 and then square to get 4.

So the first step, there are two numbers that square to give 4, that is: +2 or -2. We write these as ±2\pm 2, it's saying "2 or -2" are solutions to the equation y^2 = 4.


thank ou everyone, i just got one more question before i move on
the question is

2x^2 - x - 6 = 0

using the quadratic formula i got x = -2 and x= 1.5
when i factorised it i got x=2 and x=-1.5

when i look at the answer which used the quad formula

the -b was 1 instead of -1? how?
-b would be indeed 1 as it is -1(-1) = 1
Reply 9
Original post by eternaforest
You really didn't know that (-2)^2 and 2^2 = 4?

Posted from TSR Mobile


i know that, my question was worded awkwardly, i was just wondering if its ok to just write one value instead of two :redface:
Because the coefficient of the x was -1 so b= -1 and so -b = 1.
Reply 11
Look at your equation, that is:

2x^2 + (-1)x + (-6) = 0.

So a = 2, b =-1, c = -6.

So b=(1)=+1-b = -(-1) =+ 1.
Original post by 34908seikj
-b would be indeed 1 as it is -1(-1) = 1


Original post by Zacken
Look at your equation, that is:

2x^2 + (-1)x + (-6) = 0.

So a = 2, b =-1, c = -6.

So b=(1)=+1-b = -(-1) =+ 1.



ahhh, these little details can give me wrong answers which scares me from maths :redface:
If it's a quadratic question then you'll probably always need to give the two answers but in general when you have rt4 you don't have to put +/-2

But you've probably already know this as someone posted it already :tongue:

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Real fun starts when you solve equations like x2+2x+2=0 x^2+2x+2=0
Original post by RDKGames
Real fun starts when you solve equations like x2+2x+2=0 x^2+2x+2=0


I see what you did there :wink:
Original post by Zacken
Look at your equation, that is:

2x^2 + (-1)x + (-6) = 0.

So a = 2, b =-1, c = -6.

So b=(1)=+1-b = -(-1) =+ 1.


Original post by 34908seikj
-b would be indeed 1 as it is -1(-1) = 1


Original post by Vikingninja
Because the coefficient of the x was -1 so b= -1 and so -b = 1.


Original post by SeanFM
I see what you did there :wink:


hai lovely maths peepo i have a question, im trying to complete the square of 3[(x-2)^2 - 4x + 17/3]but i dont understand whether you half 4 or -4?
Reply 18
I would expand the whole (x-2)^2 out to get: 3[x28x+293]3\bigg[x^2 -8x + \frac{29}{3}\bigg] then you'd be halving 8-8 to get 3[(x4)2+]3\bigg[(x-4)^2 + \cdots \bigg]
Neither. To me, it looks like you need to expand the brackets (x-2)^2 first.

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