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C3 functions

http://www.examsolutions.net/a-level-maths-papers/Edexcel/Core-Maths/Core-Maths-C3/2011-January/paper.php#Q6

6c what am i supposed to do?
i mean i can find the equation of both lines but how can that help me?
gg(2)=g(g(2)). g(2)=0, so find g(0).
Original post by bigdonger
how do i know this? just a fact?


If you read the graph of g(x), 2 on the x-axis is at 0 on the y, hence g(2)=0.
Original post by bigdonger
how do i know this? just a fact?


From the graph, it passes through (2,0).
Reply 4
Avatar for asinghj
asinghj
16
Original post by bigdonger
http://www.examsolutions.net/a-level-maths-papers/Edexcel/Core-Maths/Core-Maths-C3/2011-January/paper.php#Q6

6c what am i supposed to do?
i mean i can find the equation of both lines but how can that help me?


As mentioned above, gg(2) = g(g(2)) and you should work from inside out, so g(2) first, which from the graph is 0 (when x is 2, y is 0). Then you do g(0) which is -6 (when x is 0, y is -6)
Reply 5
Avatar for bigdonger
bigdonger
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2
Original post by an_atheist
If you read the graph of g(x), 2 on the x-axis is at 0 on the y, hence g(2)=0.


Original post by HapaxOromenon3
From the graph, it passes through (2,0).


ah thanks
Reply 6
Avatar for bigdonger
bigdonger
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2
Original post by asinghj
As mentioned above, gg(2) = g(g(2)) and you should work from inside out, so g(2) first, which from the graph is 0 (when x is 2, y is 0). Then you do g(0) which is -6 (when x is 0, y is -6)


What's the purpose of me doing this?
Original post by bigdonger
What's the purpose of me doing this?


gg(2)=g(g(2). g(2)=0, therefore by substitution, gg(2)=g(0)=-6
Reply 8
Avatar for bigdonger
bigdonger
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2
Original post by an_atheist
gg(2)=g(g(2). g(2)=0, therefore by substitution, gg(2)=g(0)=-6


ah i see thanks
Reply 9
Avatar for asinghj
asinghj
16
Original post by bigdonger
What's the purpose of me doing this?


Because they want gg(2) which is g(g(2)) and focusing on g of 2 you get 0 and so putting 0 instead of g(2) on the g(g(2)) you get g(0) which is -6
(edited 7 years ago)
Reply 10
Avatar for bigdonger
bigdonger
OP
2
Original post by asinghj
Because they want gg(2) which is g(g(2)) and focusing on g of 2 you get 0 and so putting 0 instead of g(2) on the g(g(2)) you get g(0) which Is 6


thanks

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