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Tough Differentiation Q

Hi, I was wondering how to differentiate cube root 4x^4. Ive tried using the chain rule, but I just cant seem to get the answer?
(edited 7 years ago)
Original post by RNVS_99
Hi, I was wondering how to differentiate cube root 4x^4. Ive tried using the chain rule, but I just cant seem to get the answer?


How did you apply the chain rule? Please show working.
Original post by RNVS_99
Hi, I was wondering how to differentiate cube root 4x^4. Ive tried using the chain rule, but I just cant seem to get the answer?


4x43=41/3x4/3\sqrt[3]{4x^4} = 4^{1/3}\cdot x^{4/3}

Why are you even using the chain rule...?
Reply 3
Original post by RNVS_99
Hi, I was wondering how to differentiate cube root 4x^4. Ive tried using the chain rule, but I just cant seem to get the answer?


Hint: 4x43=(4x4)13\sqrt[3]{4x^4} = (4x^4)^\frac{1}{3}.

Do you see where to go from there?
Reply 4
Original post by RDKGames
4x43=41/3x4/3\sqrt[3]{4x^4} = 4^{1/3}\cdot x^{4/3}

Why are you even using the chain rule...?


Its a function within a function, so I thought the chain rule would be appropriate, but Im not to sure anyway?
Original post by RNVS_99
Its a function within a function, so I thought the chain rule would be appropriate, but Im not to sure anyway?


You can use the chain rule, sure, but since there is no constant inside this cube root then you can do this instead as it's faster since you can split the terms.
Reply 6
Original post by marioman
Hint: 4x43=(4x4)13\sqrt[3]{4x^4} = (4x^4)^\frac{1}{3}.

Do you see where to go from there?


Thats exactly what I did, but I cant get the answer of 4/3 cube root 4x
dy/dx = nx^n-1
Reply 8
Original post by RDKGames
You can use the chain rule, sure, but since there is no constant inside this cube root then you can do this instead as it's faster since you can split the terms.


I still cant manage to get the answer of 4/3 cube root 4x
Original post by RNVS_99
I still cant manage to get the answer of 4/3 cube root 4x


That's not the full answer. Show us your working out.
Reply 10
Original post by RDKGames
That's not the full answer. Show us your working out.


The answer is 4/3 cube root 4x as it says in the book
Reply 11
Original post by RDKGames
That's not the full answer. Show us your working out.


I dont know how to get the answer, which is why I am asking
Original post by RNVS_99
I dont know how to get the answer, which is why I am asking


If you're going with the form I've demonstrated then know that:

ddx(axn)=anxn1\frac{d}{dx}(ax^n)=a \cdot n \cdot x^{n-1}

Show us you applying this to the question.
Reply 13
Original post by RDKGames
If you're going with the form I've demonstrated then know that:

ddx(axn)=anxn1\frac{d}{dx}(ax^n)=a \cdot n \cdot x^{n-1}

Show us you applying this to the question.


So far, my answer is 4/3^-2/3 * 4x/3^1/3
Am I right so far??
Original post by RNVS_99
So far, my answer is 4/3^-2/3 * 4x/3^1/3
Am I right so far??


No. I'm not quite sure why you reduced the exponent on the 4...

ddx(41/3x4/3)=41/343x1/3\frac{d}{dx}(4^{1/3} \cdot x^{4/3})=4^{1/3} \cdot \frac{4}{3} \cdot x^{1/3}
Reply 15
Original post by RDKGames
No. I'm not quite sure why you reduced the exponent on the 4...

ddx(41/3x4/3)=41/343x1/3\frac{d}{dx}(4^{1/3} \cdot x^{4/3})=4^{1/3} \cdot \frac{4}{3} \cdot x^{1/3}


ahh okay, I see, cant you then multiply the 4 and the x, giving you the cube root 4x?
Original post by RNVS_99
ahh okay, I see, cant you then multiply the 4 and the x, giving you the cube root 4x?


Indeed. I've misread your previous answer, could help to use latex.
Reply 17
Original post by RDKGames
Indeed. I've misread your previous answer, could help to use latex.


haha, sorry about that, thanks for the help, this question confused me a bit, but now I understand it!

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