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Really stuck need maths genius

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Original post by RDKGames
Huh? Mate you need to check your maths: (a+b)2=a2+b2(a+b)^2=a^2+b^2 so a+b=a2+b2=a+ba+b=\sqrt{a^2+b^2}=a+b


I thought it was right.
Original post by physicsmaths
Long time no see :smile:


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Indeed. Excited for results day?


Original post by gdunne42
That's wrong (6x+3)^2 = (6x+3)(6x+3), expand the brackets


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I'd stop wasting energy - this thread is not to be taken seriously, it seems 🙄
Original post by RDKGames
Huh? Mate you need to check your maths: (a+b)2=a2+b2(a+b)^2=a^2+b^2 so a+b=a2+b2=a+ba+b=\sqrt{a^2+b^2}=a+b


No I don't mate, you do.


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Original post by gdunne42
That's wrong (6x+3)^2 = (6x+3)(6x+3), expand the brackets


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Yeah you're right there. Damn my maths is rusty lol :colondollar:
In that case, the answer should be:

x = (-12+sqrt(87612))/74 or
= (-12-sqrt(87612))/74
Hi,

As said above the square root of y² +x² is not y + x.
You can either use quadratic formula as some others have stated or take out a factor of 'a' and be left with a quadratic without the number in front of the x² term.

Hope that helps a bit
Original post by gdunne42
No I don't mate, you do.


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You must've been taught wrong. It's all common sense (a+b)2(a+b)^2 means you square the a and then add on the square of b. Go back to textbooks, gg.
Original post by SeanFM
Indeed. Excited for results day?




I'd stop wasting energy - this thread is not to be taken seriously, it seems 🙄


Excited :/ lol.
Probably gna be in clearing with like 3A*s and 111 in step I-III minimum 😂.
But seriosuly yeh i know i have minimum 1,1,1 in step and i dnt even know about AFM since i flopped modules like D1 D2 and S4 like got U in D1 😂(what did i expect not touching the module at all :frown:) so i either get A* or a B since M3/4 r probably 100ums and M5 well made a mistake on a 10 marker so yh :/.
So hopefully cam still accept me if i did flop a levels like I feared I would.



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Original post by RDKGames
You must've been taught wrong. It's all common sense (a+b)2(a+b)^2 means you square the a and then add on the square of b. Go back to textbooks, gg.


Not wasting any more time on this troll thread


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(edited 7 years ago)
Original post by gdunne42
You trolling or you want me to find you a text book example?


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...

What do you think?
Original post by RDKGames
...

What do you think?


Nothing worse that bored maths students waiting for exam results.


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Reply 30
Avatar for Ayman!
Ayman!
15
Original post by gdunne42
The square root of x^2 + y^2 is not x + y

Try it, 64 + 36 = 100 the square root is 10. It is not 8 + 6


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Spoiler

Original post by gdunne42
Not wasting any more time on this troll thread


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Sincerly sorry for this thread.
Especially for wasting your time when you geniunely want to help.
I got nothing better to do since I don't want to learn Analysis.


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Reply 32
Avatar for Zacken
Zacken
22
Original post by gdunne42
Not wasting any more time on this troll thread


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To be fair, (a+b)2=a2+b2(a+b)^2 = a^2 + b^2 in a field of characteristic 22.
The problem is simple, intersections of a line and circle, just big numbers. Substitute x^2 + (6x +3)^2 = 600, x^2 + 36x^2 + 36x +9 = 600, 37x^2 + 36x - 591 = 0. Now solve with the quadratic formula, x = (-36 +- sqrt ( 1296 + 4 * 37 * 591))/ 2 * 37 = (-36 +- 297.93) / 74, x = -4.51, 3.54. Now substitute in y = 6x + 3. (-4.51, -24.06), (3,54, 24.24) are the approximate intersection points.

Use standard substitution method. Do not be intimidated by big numbers.
Original post by mathplustutornj
The problem is simple, intersections of a line and circle, just big numbers. Substitute x^2 + (6x +3)^2 = 600, x^2 + 36x^2 + 36x +9 = 600, 37x^2 + 36x - 591 = 0. Now solve with the quadratic formula, x = (-36 +- sqrt ( 1296 + 4 * 37 * 591))/ 2 * 37 = (-36 +- 297.93) / 74, x = -4.51, 3.54. Now substitute in y = 6x + 3. (-4.51, -24.06), (3,54, 24.24) are the approximate intersection points.

Use standard substitution method. Do not be intimidated by big numbers.


Did you even read any of the comments on this thread? :facepalm:
You're all wrong!

(a+b)^2 = a^2 + 2ab + b^2
= 2 + a^2 + a + b^2 + b
= 2 + a^3 + b^3
Original post by RDKGames
Did you even read any of the comments on this thread? :facepalm:


Is my solution wrong? This is a simple problem of the intersection of a circle and a line. I see some people were discussing a solution along the lines I mentioned. If you had y = x +1 and x^2 + y^2 =9, you would solve it the same way. In the problem given, the numbers are bigger, but it is a simple problem.
Original post by mathplustutornj
Is my solution wrong? This is a simple problem of the intersection of a circle and a line. I see some people were discussing a solution along the lines I mentioned. If you had y = x +1 and x^2 + y^2 =9, you would solve it the same way. In the problem given, the numbers are bigger, but it is a simple problem.


No, your solution and method are fine. The OP was joking with the question, he didn't need help with it. :colonhash:
Original post by RDKGames
No, your solution and method are fine. The OP was joking with the question, he didn't need help with it. :colonhash:


Yeh i did actually. I was proper stuck


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