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Maths year 11

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Reply 860
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z_o_e
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11
Original post by RDKGames
Alright turn these into fractions:

(a) 0.145

EXAMPLE:
0.145=0.1451=1451000=292000.145=\frac{0.145}{1}=\frac{145}{1000}=\frac{29}{200}

(b) 0.1

(c) 0.65

(d) 0.841

..and a bit more challenging in the mix

(e) 0.333˙...0.33\dot3...


What did you do after 145/1000 the 29 bit I didn't understand it.
Reply 861
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z_o_e
OP
11
Original post by RDKGames
Alright turn these into fractions:

(a) 0.145

EXAMPLE:
0.145=0.1451=1451000=292000.145=\frac{0.145}{1}=\frac{145}{1000}=\frac{29}{200}

(b) 0.1

(c) 0.65

(d) 0.841

..and a bit more challenging in the mix

(e) 0.333˙...0.33\dot3...




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Original post by z_o_e
What did you do after 145/1000 the 29 bit I didn't understand it.


I divided top and bottom by 5 in order to simplify it down.
Reply 863
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z_o_e
OP
11
Original post by RDKGames
I divided top and bottom by 5 in order to simplify it down.




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Original post by z_o_e


Looks good. Though for the first one it should be 200, not 100, on the denominator. :smile:
Reply 865
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z_o_e
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11
Original post by RDKGames
Looks good. Though for the first one it should be 200, not 100, on the denominator. :smile:


What do I do with the 841 one?

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Original post by z_o_e
What do I do with the 841 one?

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Just leave it as it is. 841 is a prime number so you cannot reduce that fraction any further.


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Reply 867
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z_o_e
OP
11
Original post by RDKGames
Just leave it as it is. 841 is a prime number so you cannot reduce that fraction any further.


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What about E

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Original post by z_o_e


Slightly trickier method:

x=0.333....
10x=3.333...
---------------------------
Take x away from 10x
9x=3
x=3/9=1/3=0.333....
Reply 869
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z_o_e
OP
11
Original post by RDKGames
Slightly trickier method:

x=0.333....
10x=3.333...
---------------------------
Take x away from 10x
9x=3
x=3/9=1/3=0.333....


I don't understand where X and 10 comes from and how you work it out?
Original post by z_o_e
I don't understand where X and 10 comes from and how you work it out?


That's the trick.

If we let x=0.333...x=0.333... then we can get 10x by multiplying both sides by 10; hence where 3.333... comes from. Then when we subtract x from 10x, all the decimal places cancel out and we are left with 3 because 3.333... - 0.333... = 3
Reply 871
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z_o_e
OP
11
Original post by RDKGames
That's the trick.

If we let x=0.333...x=0.333... then we can get 10x by multiplying both sides by 10; hence where 3.333... comes from. Then when we subtract x from 10x, all the decimal places cancel out and we are left with 3 because 3.333... - 0.333... = 3


Can you do more examples of these please on a piece of paper?
Original post by RDKGames
That's the trick.

If we let x=0.333...x=0.333... then we can get 10x by multiplying both sides by 10; hence where 3.333... comes from. Then when we subtract x from 10x, all the decimal places cancel out and we are left with 3 because 3.333... - 0.333... = 3

You could consider the sum of the geometric series ∑n=1∞(3×10−n) \displaystyle \sum_{n=1}^{\infty} (3\times10^{-n}) .
Original post by z_o_e
Can you do more examples of these please on a piece of paper?


Try finding fraction equivalent to 0.9˙ 0.\dot{9} .
Original post by Ano123
You could consider the sum of the geometric series ∑n=1∞(3×10−n) \displaystyle \sum_{n=1}^{\infty} (3\times10^{-n}) .


I could. But I choose not to for a GCSE student.
Original post by RDKGames
I could. But I choose not to for a GCSE student.


Yah I know but I bet you never considered it this way before.
Original post by z_o_e
Can you do more examples of these please on a piece of paper?


Try turning these into fractions and use the examples below for help:

(a) 0.5˙0.\dot5
(b) 0.5˙8˙0.\dot5\dot8
(c) 0.9˙8˙0.\dot9\dot8
(c) 0.2˙45˙0.\dot24\dot5

Spoiler


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(edited 7 years ago)
Reply 877
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z_o_e
OP
11
Original post by RDKGames
Try turning these into fractions and use the examples below for help:

(a) 0.5˙0.\dot5
(b) 0.5˙8˙0.\dot5\dot8
(c) 0.9˙8˙0.\dot9\dot8
(c) 0.2˙45˙0.\dot24\dot5

Spoiler


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Could you check this please.
I will do those in a bit


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1471204554223.jpg32.0KB
Original post by z_o_e
Could you check this please.
I will do those in a bit


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Good


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I was the same in year 10, I didn't realise how important Maths was until I was halfway through year 11. I was getting D's and C's in year 10 and half of year 11, but in January I realised I was under achieving and I was doubting my abilities, so from January I started working on the subject I found most difficult, and even though I didn't like my teacher I asked for her help, and I was persistant with my studying at home and I was achieving high B's and well onto A's by the time I sat my exams in June, so you can do it. My best advice is to practise exam paper questions and always practise the topics you find most difficult. Good Luck 😄

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