Maths year 11

How would I do question 4 though?

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If the length is being rounded to 1dp then you look at the second decimal place to decide how it should be rounded. You know like 5.06 is 5.1 to one decimal place. And 5.01 is 5.0 to one decimal place. So the answer will be 2.0X where X represents some digit. Hope this makes Sense.

I got this.


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If you rounded your upper bound to 1dp you would get 3. You should be adding and subtracting 0.05cm not 0.5cm as the length itself is rounded to 1dp.

If you rounded your upper bound to 1dp you would get 3. You should be adding and subtracting 0.05cm not 0.5cm as the length itself is rounded to 1dp.

Oh okay X

Can you check these please


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I did that question

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These look fine.



What's the question for this?

The question was


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So we need to find the upper bound here. As its rounded to 1dp we need to add 0.05 to it because we would round anything less than 2.05cm down to 2.0cm.

I don't really get this

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Ohhh I was suppose to add the lines downwards
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I did it like this.. I took the decimals out.
But my final answer can move the two decimal places into the final answer.

But I got it wrong

I did it on my whiteboard and I got it right.


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Here I did question 3
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I got this.Posted from TSR Mobile

You can do either downwards or sideways when you add them up. The problem you had on paper was that when you added sideways, you said that 500+50+25 was 625 when it is NOT. It's 575. The other two are correct and you can add them, you'd get the right answer that way which you'd need to divide by a 100 for the decimal.



This is incorrect. Each length has been rounded to the nearest metre so you need to find the upper bounds of EACH LENGTH and then multiply them together.
That's incorrect. For that one you are looking for 2 bounds between which all the numbers would round to 2.7.Here's an example. For 1, the LB is 0.5 and UB is 1.5. What about something like 2.5? Well we know that 2.45 will round to it and numbers less than 2.55 will do as well. So those are out bounds. Rather than adding/subtracting 0.5 from our original value, in this case it;s 0.05.

Okay let's start off with question 3

What's the first step?



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Firstly, notice that the question wants the largest possible volume, therefore how do we get the largest possible volume? By taking the upper bounds of each length.

Yep. Now imagine these are the lengths of that cuboid and the volume of that cuboid will be the largest possible one for the original question.

I multiply all the answers to get the largest volume possible?

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Yep.