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Maths year 11

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Reply 1360
Original post by RDKGames
ba+2a=2a2bba+2a=2a^2b ??? You're not multiplying them here.


Then how do I add them?

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Original post by z_o_e
Then how do I add them?

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Well certainly not by multiplying them, that's a whole other operation. :tongue:

It's just that, though you can factor out the a which is helpful to simplify the overall fraction further.
Reply 1362
Original post by RDKGames
Well certainly not by multiplying them, that's a whole other operation. :tongue:

It's just that, though you can factor out the a which is helpful to simplify the overall fraction further.


3ab?

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No. ab+2a=a(b+2)ab+2a=a(b+2)

a(b+2)2a=b+22\rightarrow \frac{a(b+2)}{2a} = \frac{b+2}{2}
Reply 1364
Original post by RDKGames
No. ab+2a=a(b+2)ab+2a=a(b+2)

a(b+2)2a=b+22\rightarrow \frac{a(b+2)}{2a} = \frac{b+2}{2}


Is that the final answer?

So do I do the rest just like the same way?

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Original post by z_o_e
Is that the final answer?

So do I do the rest just like the same way?

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Yes. That would be the final simplified answer.
Reply 1366
Original post by RDKGames
Yes. That would be the final simplified answer.


Okay can you do a quick example on root 500 and simplifying it. On paper please x

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Reply 1367
Original post by RDKGames
Yes. That would be the final simplified answer.


I can't really factories this and the numerators have no like terms



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Reply 1368
Original post by RDKGames
Yes. That would be the final simplified answer.


I can't really factories this and the numerators have no like terms...



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Original post by z_o_e
Okay can you do a quick example on root 500 and simplifying it. On paper please x

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Lol sure, root 500 it is then.
Attachment not found


Also that fraction with a, b, c and d cannot be factorised any further. Just make it a single fraction and you're done


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(edited 7 years ago)
Original post by z_o_e
I can't really factories this and the numerators have no like terms...



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ImageUploadedByStudent Room1471987054.242615.jpg


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Reply 1371
Original post by z_o_e
Hmmm confusing.


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What's confusing about it? I'm splitting 500 into 2 and 250 as they make up the 500. Obviously I cannot decompose the 2 any further so I split the 250 into 2 and 125, and finally I split 125 into 5 and 25. There are all surds multiplied together so I just simplify the one's I can.
Reply 1373
Original post by RDKGames
What's confusing about it? I'm splitting 500 into 2 and 250 as they make up the 500. Obviously I cannot decompose the 2 any further so I split the 250 into 2 and 125, and finally I split 125 into 5 and 25. There are all surds multiplied together so I just simplify the one's I can.


Doesn't 25 decompose into 5 and 5

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Original post by z_o_e
Doesn't 25 decompose into 5 and 5

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Yeah. But for one, I know that 25 is a square number so when it is square rooted, I would just get 5.

Otherwise, I could've written it as root 5 times root 5 but I would've gotten a 5 out of these two multiplied. I just skipped this step.
Reply 1375
Original post by RDKGames
Yeah. But for one, I know that 25 is a square number so when it is square rooted, I would just get 5.

Otherwise, I could've written it as root 5 times root 5 but I would've gotten a 5 out of these two multiplied. I just skipped this step.


So using these circled numbers how would I find simplified of 500?


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Original post by z_o_e
So using these circled numbers how would I find simplified of 500?


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It would be 500=22555\sqrt{500}=\sqrt2 \cdot \sqrt2 \cdot \sqrt5 \cdot \sqrt5 \cdot \sqrt5 then just simplify whatever you can.
Reply 1378
Original post by RDKGames
It would be 500=22555\sqrt{500}=\sqrt2 \cdot \sqrt2 \cdot \sqrt5 \cdot \sqrt5 \cdot \sqrt5 then just simplify whatever you can.


What about this?


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Original post by z_o_e
What about this?


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Correct method except you must've gotten carried away because at the very bottom, 5 and 5 do not make up 10 with multiplication.

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