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Gradient question help!!

Hi , im stuck on this question :
Find the gradient of the lines joining the following pairs of points:
A=(p+3,q-7)
B=(p+5,3-q )
y2-y1/x2-x1
you have your co-ordinates, put it into this equation, you will have your answer :wink:
The Gradient of the line joining 2 points is the change in Y value divided by the change in X value.

To find the change of either value, just take one away from the other. (y1-y2)/(x1-x2)

So,

(P+3)-(P+5) = P + 3 - P - 5 = -2. Change in X = -2

(Q-7)-(3-Q) = Q - 7 - 3 + Q = 2Q -10 Change in Y= 2Q-10

Therefore

Gradient = (2Q-10) / (-2)

Becoming

-Q + 10
Original post by Workaholism
(FULL SOLUTION)


That's some nice working out. Can you solve this for me? I need the general solution. Thanks.

4xd2ydx2+2(1−2x)dydx+y=3x\displaystyle 4x\frac{d^2y}{dx^2}+2(1-2\sqrt{x})\frac{dy}{dx}+y=3\sqrt{x} using substitution x=t2x=t^2?


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(edited 7 years ago)
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B_9710
18
Original post by RDKGames
That's some nice working out. Can you solve this for me? I need the general solution. Thanks.

4xd2ydx2+2(1−2x)dydx+y=3x\displaystyle 4x\frac{d^2y}{dx^2}+2(1-2\sqrt{x})\frac{dy}{dx}+y=3\sqrt{x} using substitution x=t2x=t^2?

Spoiler

Spoiler

(edited 7 years ago)
Original post by RDKGames
That's some nice working out. Can you solve this for me? I need the general solution. Thanks.

4xd2ydx2+2(1−2x)dydx+y=3x\displaystyle 4x\frac{d^2y}{dx^2}+2(1-2\sqrt{x})\frac{dy}{dx}+y=3\sqrt{x} using substitution x=t2x=t^2?

Spoiler



Huh? Why not?
Original post by Workaholism
Huh? Why not?


Well apart from it being against the posting rules, you are also doing the question for the person. Just give them hints like the first reply and let them figure it out on their own.

Original post by B_9710

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B_9710
18
Original post by RDKGames
Well apart from it being against the posting rules, you are also doing the question for the person. Just give them hints like the first reply and let them figure it out on their own.

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Spoiler

Original post by B_9710

Spoiler


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B_9710
18
Original post by RDKGames

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No.
Original post by B_9710
No.


Well damn, if Wolfram Alpha doesn't give me the right answer I don't know what will. :smile:
Reply 11
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Zacken
22
Alright, enough with the off topic DE's, don't you think?
Reply 12
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B_9710
18
Original post by Zacken
Alright, enough with the off topic DE's, don't you think?


They're spoilered so it's fine.
Original post by Workaholism
The Gradient of the line joining 2 points is the change in Y value divided by the change in X value.

To find the change of either value, just take one away from the other. (y1-y2)/(x1-x2)

So,

(P+3)-(P+5) = P + 3 - P - 5 = -2. Change in X = -2

(Q-7)-(3-Q) = Q - 7 - 3 + Q = 2Q -10 Change in Y= 2Q-10

Therefore

Gradient = (2Q-10) / (-2)

Becoming

-Q + 10


Your final answer should be -Q + 5, as (-10)/(-2) = 5.

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