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How do you re-arrange these equations, plz help

𝑎𝑥 − 𝑥/𝑏 + 𝑏^2= 𝑎^2 (x)
2𝑥^2 𝑦 − 5𝑥𝑦 = 3 (y)
(edited 7 years ago)
Original post by p29
𝑎𝑥 − 𝑥 𝑏 + 𝑏 2 = 𝑎 2 (x)
2𝑥^2 𝑦 − 5𝑥𝑦 = 3 (y)


Remember that ax+bx = (a+b)x
That technique is used for both
Original post by p29
𝑎𝑥 − 𝑥 𝑏 + 𝑏 2 = 𝑎 2 (x)
2𝑥^2 𝑦 − 5𝑥𝑦 = 3 (y)


Re-arrange for what?
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p29
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Original post by RDKGames
Re-arrange for what?

x and y
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p29
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Original post by ValerieKR
Remember that ax+bx = (a+b)x
That technique is used for both

i cant find a common factor for 2 and 5
Original post by p29
i cant find a common factor for 2 and 5


The common factor is y
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p29
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Original post by ValerieKR
The common factor is y

ugh i wrote the question wrong
Reply 7
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p29
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wtf even is this????????
Original post by p29
wtf even is this????????


ax−xb+b2=a2ax-\frac{x}{b}+b^2=a^2

x(a−1b)+b2=a2x(a-\frac{1}{b})+b^2=a^2

You can finish up the rest. It's nothing more complicated than that.
Reply 9
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Zacken
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Eh, why are you replying? This is the same stupid troll from last time.
Original post by Zacken
Eh, why are you replying? This is the same stupid troll from last time.


Last time?
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Zacken
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Original post by RDKGames
Last time?


http://www.thestudentroom.co.uk/showthread.php?t=4286748
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p29
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Original post by RDKGames
ax−xb+b2=a2ax-\frac{x}{b}+b^2=a^2

x(a−1b)+b2=a2x(a-\frac{1}{b})+b^2=a^2

You can finish up the rest. It's nothing more complicated than that.

thx
Original post by Zacken


Oh, forgot that was him there.
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:biggrin:
Reply 15
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Original post by p29
:biggrin:


:shoot:
Reply 16
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p29
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Original post by Zacken
:shoot:

:rip:

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