I'm confused why the bromine atoms are placed on either side of the benzene molecule.
Thanks.
The -OH group attached to the benzene ring is 2,4,6 directing and activating. Hence the tendency would be for triple substitution, but in this case the 4- position is already taken up so substitution happens at only the 2 and 6 positions of the ring.
The -OH group attached to the benzene ring is 2,4,6 directing and activating. Hence the tendency would be for triple substitution, but in this case the 4- position is already taken up so substitution happens at only the 2 and 6 positions of the ring.
The -OH group attached to the benzene ring is 2,4,6 directing and activating. Hence the tendency would be for triple substitution, but in this case the 4- position is already taken up so substitution happens at only the 2 and 6 positions of the ring.
Hold on the Br groups are only at the 2 and the 5 positions. how is this the case. It is not 6.
No I think because the OH is 2 and 4 activating but so is the -NHR group which also does the same job.
The Br is in position 2 from the -OH and so the -NHR group is in 4 if seen anticlockwise (Down then up)
Hold on the Br groups are only at the 2 and the 5 positions. how is this the case. It is not 6.
No I think because the OH is 2 and 4 activating but so is the -NHR group which also does the same job.
The Br is in position 2 from the -OH and so the -NHR group is in 4 if seen anticlockwise (Down then up)
Please help!
The Brs are at the 2 and 6 positions, with the -OH attached at 1. Count again.
It's an -NHCOR group which is o/p directing but not as strongly as -OH (think of this in terms of how much electron density is donated to the π system).
The Brs are at the 2 and 6 positions, with the -OH attached at 1. Count again.
It's an -NHCOR group which is o/p directing but not as strongly as -OH (think of this in terms of how much electron density is donated to the π system).
Got it. Now it makes sense perfectly. Thanks very much