C3 Iteration

For each equation, show that it can be rearranged into the given iterative form.

tanx − 5x + 13 = 0

x_{n + 1} = arctan (5_xn − 13)

Can someone explain why the tan turns into arctan? I thought it would just be tan^-1...

I haven't done the trigonometry topic yet so if this is covered there then thats probably why i'm confused...

Reply 1

solC

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Original post by jessyjellytot14

For each equation, show that it can be rearranged into the given iterative form.

tanx − 5x + 13 = 0

x_{n + 1} = arctan (5_xn − 13)

Can someone explain why the tan turns into arctan? I thought it would just be tan^-1...

I haven't done the trigonometry topic yet so if this is covered there then thats probably why i'm confused...

arctan(x) is the same as tan^-1(x), if that's what you mean :smile:

Original post by jessyjellytot14

For each equation, show that it can be rearranged into the given iterative form.

tanx − 5x + 13 = 0

x_{n + 1} = arctan (5_xn − 13)

Can someone explain why the tan turns into arctan? I thought it would just be tan^-1...

I haven't done the trigonometry topic yet so if this is covered there then thats probably why i'm confused...