Basic simultaneous question - I am stuck, please explain the solution to this!

Simultaneous equation:

3x-2y=4
2x+3y=-6

So I multiplied the top by 3 and the bottom by 2 in order to get the Y's the same:

9x-6y=12
4x+6y=-12

And then the signs are different, so you add them together and get:

13x=0

How do you do this one? Is it as simple as x=0, so then you substitute x=0 into the equation to find out y?

Am I just derping?

SOrry for the dumb question.

A good way to test your solution is to put it back into both of the original equations. After all, that's what you're finding