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Solve using the quadratic equation

3x^2-3x-7=0
please help
Original post by AlevelMaths42
please help


What's the quadratic formula?
What are your a, b and c values?

Let's see what you think.
Reply 3
Avatar for Jehaan
Jehaan
19
If I remember correctly the quadratic formula is -b x root (b^2-4ac)/2a
I don't have a calculator but just put the values in and remember to do plus and minus the value of b
Original post by AlevelMaths42
3x^2-3x-7=0


Just use the formula x = {-b +_ sqrt(b2-4ac)}/2a where a=3, b=3 c=7 and you'll get the values of x.


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quad.jpg
Original post by wightsnowolf
...


Nice. Can I get you to do my homework for me too, please?
x=(3+sqrt93) all over 6
x=(3-sqrt93) all over 6


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Reply 8
Avatar for Aklaol
Aklaol
12
Original post by Jehaan
If I remember correctly the quadratic formula is -b x root (b^2-4ac)/2a
I don't have a calculator but just put the values in and remember to do plus and minus the value of b



[QUOTE="RossB1702;67530608"]Just use the formula x = {-b +_ sqrt(b2-4ac)}/2a where a=3, b=3 c=7 and you'll get the values of x

Please never write it out like that again.
[QUOTE="Aklaol;67531964"]
Original post by RossB1702
Just use the formula x = {-b +_ sqrt(b2-4ac)}/2a where a=3, b=3 c=7 and you'll get the values of x

Please never write it out like that again.


Lol I'm on iPhone. Did I cut you deep man lmao.


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Reply 10
Avatar for Aklaol
Aklaol
12
[QUOTE="RossB1702;67531996"]
Original post by Aklaol


Lol I'm on iPhone. Did I cut you deep man lmao.


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You did. Next time you slip up like this, I'm gonna get mans on you.
[QUOTE="Aklaol;67532022"]
Original post by RossB1702


You did. Next time you slip up like this, I'm gonna get mans on you.


The fears hut me mate haha.


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