Direction is the angle, once you find out all 3 sides of the right angles triangle by using pythagoraus then you can use tan x = o/h to find the angle O = side opposite angle H = hypotneuse Then do inverse tan x to find x
I have no idea, I've just been set this work in prep for starting a level.
Heard of logarithms before and I think it was from a-level maths. So probably go on exam solutions and go to the index and find logs, then see if you can turn what it's saying into a straight line equation then you u should be good from there my bridging work was just some advanced gcse stuffy and a few easy a-level stuff like suvat
I looked online, but can only find logs with numbers, never things like N and NO
Okay, since you're struggling to gain a footing, I'll explain the answer to you.
Logarithms are essentially the inverse of exponentiation, so we can use them to construct direct, linear proportionalities from exponential relations. Know that the natural logarithm (ln) is log of base e, such that ln(e) = 1.
In this equation, N is the variable to track, whereas N0 is the initial value of N. It's not clear which of h and g is variable or constant, but let's assume g is variable.
ln(N) = ln(N0e^-hg)
ln(N) = ln(N0) + ln(e^-hg)
ln(N) = ln(N0) - hg ln(e)
ln(N) = ln(N0) - hg
It is evident that: ln(N) ∝ -g Thus, we can plot a straight line of ln(N) against -g, with gradient h and y-intercept ln(N0), allowing to easily determine those values if necessary.