3. A uniform lamina ABC of mass m is in the shape of an isosceles triangle with
AB = AC = 5a and BC = 8a. (a) Show, using integration, that the moment of inertia of the lamina about an axisthrough A, parallel to BC, is 92 ma2 .
The answer should read (9/2)ma^2. In the mark scheme for this question it makes no reference to the use of the standard result for a uniform rod of length 2l, and neither does the question, and yet surely this is essential since you need the summation of all the strip's moment of inertia to get the total moment of inertia.
Thank you in advance!!!!