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Quadratics and discriminant

Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
where m is a constant, given that it has repeated roots.

I worked out the discriminant which is b^2-4ac=0
So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
Not sure what to do from here.
Thanks!
Original post by algebrax1
Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
where m is a constant, given that it has repeated roots.

I worked out the discriminant which is b^2-4ac=0
So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
Not sure what to do from here.
Thanks!


The quadratic expression should be equal to 0.
Original post by algebrax1
Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
where m is a constant, given that it has repeated roots.

I worked out the discriminant which is b^2-4ac=0
So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
Not sure what to do from here.
Thanks!


a=1[br]b=3−m[br]c=5−m2a=1[br]b=3-m[br]c=5-m^2

Now try again.

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