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Differentiation help

junayd1998

I don't understand how to do the 2/x bit could anyone explain and help please would be much appreciated

Reply 1

Zacken

Original post by junayd1998

I don't understand how to do the 2/x bit could anyone explain and help please would be much appreciated

\dfrac{2}{x} = 2x^{-1}

and you know how to differentiate

x^n

Reply 2

junayd1998

Original post by Zacken

\dfrac{2}{x} = 2x^{-1}

and you know how to differentiate

x^n

oh alright thanks yeah you will get -2^-2

Reply 3

RDKGames

Study Forum Helper

Original post by junayd1998

I don't understand how to do the 2/x bit could anyone explain and help please would be much appreciated

\frac{2}{x}=2x^{-1}

Reply 4

junayd1998

Original post by RDKGames

\frac{2}{x}=2x^{-1}

yep thank you.

Reply 5

Zacken

Original post by junayd1998

oh alright thanks yeah you will get -2^-2

Typo, I presume? You should then get

\frac{d}{dx} (2x^{-1}) = 2(-1)x^{-1-1} = -2x^{-2}

Reply 6

junayd1998

Original post by Zacken

Typo, I presume? You should then get

\frac{d}{dx} (2x^{-1}) = 2(-1)x^{-1-1} = -2x^{-2}

Oh yeah sorry forgot to add the x (typo) yep -2x^-2

Reply 7

Zacken

Original post by junayd1998

Oh yeah sorry forgot to add the x (typo) yep -2x^-2

Yep, that's right

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Differentiation help

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