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C3 graph help needed

1474838681453952323006.jpgHi I am trying to draw h(x) so I forced the bottom expression to go on the top, giving 5 as the y asymtopes. What I have done wrong ?


Thanks
Original post by coconut64
Hi I am trying to draw h(x) so I forced the bottom expression to go on the top, giving 5 as the y asymtopes. What I have done wrong ?
Thanks


y=5y=5 is not an asymptote.

lim⁡x→∞2x+1x−2=lim⁡x→∞2+1x1−2x=2\displaystyle \lim_{x\rightarrow \infty} \frac{2x+1}{x-2} = \lim_{x\rightarrow \infty} \frac{2+\frac{1}{x}}{1-\frac{2}{x}} = 2 so the asymptote is y=2y=2

With y asymptotes you are always looking for a value that the function tends towards as x goes to infinity. You can see that from your form if you separate it into 2 different fractions and get a form of 2+5x−22+\frac{5}{x-2} and the denominator goes to infinity as x goes to infinity therefore you're left with 2 since the whole fraction goes to 0.
(edited 7 years ago)
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Avatar for Zacken
Zacken
22
Original post by RDKGames
denominator goes to 0 as x goes to infinity therefore you're left with 2.


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Original post by Zacken
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*sigh*

It's been a long day, k?

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