Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

C3 differentiation

this is my answer for the differentiated form of secxcosecx but the simplied answer is just sec^2x-cosec^2x .

I don't see how can I turn secxcosecx(Tanx-Cotx) into that form . Thanks

Study Forum Helper

Original post by coconut64

this is my answer for the differentiated form of secxcosecx but the simplied answer is just sec^2x-cosec^2x .

I don't see how can I turn secxcosecx(Tanx-Cotx) into that form . Thanks

Factor out a

\cot(x)

from your final answer and use identities.

\sec(x) \csc(x) \cot(x) (\tan^2(x)-1)

So

\frac{1}{\cos(x) \sin(x)} \cdot \frac{\cos(x)}{\sin(x)} \cdot (tan^2(x)-1)

and finish it off from there

OP

Original post by RDKGames

Factor out a

\cot(x)

from your final answer and use identities.

\sec(x) \csc(x) \cot(x) (\tan^2(x)-1)

So

\frac{1}{\cos(x) \sin(x)} \cdot \frac{\cos(x)}{\sin(x)} \cdot (tan^2(x)-1)

and finish it off from there

How can you factor out COT x when there is only one COT x term ?

you can rewrite y = secx cosecx as

2/sin2x

then do a quotient rule...

y' = -4cos2x/sin²2x

y' = -4(cos²x - sin²x)/(2sinxcox)²

etc

Study Forum Helper

Original post by coconut64

How can you factor out COT x when there is only one COT x term ?

And how does that prevent you from doing so, exactly?

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