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Rate equations help

image.jpgCalculate the rate of formation of C , if 15cm3 of 0.05 mol do-3 A is mixed with 20 cM3 of 0.02 moles A dm3 B ???
Original post by Hazel99
image.jpgCalculate the rate of formation of C , if 15cm3 of 0.05 mol do-3 A is mixed with 20 cM3 of 0.02 moles A dm3 B ???


The first thing to do is the calculate the concentrations of the components after mixing (the new volume is 35 ml)
Reply 2
Avatar for Hazel99
Hazel99
OP
10
[QUOTE=charco;68035734]The first thing to do is the calculate the concentrations of the components after mixing (the new volume is 35 ml)

How?
(0.05+0.02)=0.07 conc.

Do I need to get the moles?
Original post by Hazel99
How?
(0.05+0.02)=0.07 conc.

Do I need to get the moles?


You can work it out using the moles or you can use simple proportions.

15cm3 of 0.05 mol dm-3 A is mixed with 20 cm3 of 0.02 moles dm-3 B

The new concentration of A is 0.05 x 15/35 = 0.0214 mol dm-3

The new concentration of B is 0.02 x 20/35 = 0.0114 mol dm-3

Now plug into the rate equation ...
Reply 4
Avatar for Hazel99
Hazel99
OP
10
[QUOTE=charco;68041172]You can work it out using the moles or you can use simple proportions.

15cm3 of 0.05 mol dm-3 A is mixed with 20 cm3 of 0.02 moles dm-3 B

The new concentration of A is 0.05 x 15/35 = 0.0214 mol dm-3

The new concentration of B is 0.02 x 20/35 = 0.0114 mol dm-3

Now plug into the rate equation ...

Thank you 😊

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