Sorry, just done it with partial fractions and it worked, thank you!
Out of interest though, why would that method give me a different answer? Is it because I took a value with u out of the integral? Not sure if I can do that?
Sorry, just done it with partial fractions and it worked, thank you!
Out of interest though, why would that method give me a different answer? Is it because I took a value with u out of the integral? Not sure if I can do that?
It should give you the same answer, the books are wrong sometimes
I have no idea what you are saying but I suspect it is terrible.
Did you think u(u−4)=2u−4?
No, the differential of u(u-4) is 2u - 4
I was trying to get the integral into f'(x)/f(x) form so to convert the 1 into the differential of the denominator I took out 1/2u-4, this is where my error was... It's okay I see it now xD
Sorry, just done it with partial fractions and it worked, thank you!
Out of interest though, why would that method give me a different answer? Is it because I took a value with u out of the integral? Not sure if I can do that?
When you say "take out"
Do you meant take out of the integral like you would "take out" a factor
If you wanted to avoid partial fractions you could have made a second substitution t = u-2 and then the integral is in a standard form you can look up in your formula book. Partial fractions is the easier way in my opinion though.
Do you meant take out of the integral like you would "take out" a factor
If so
NO
Yes, I see now, you can only take out constants. Thank you all! Partial fractions are the way forward! Suppose that teaches you not to do questions for which you've not yet been taught the content... Potential for hours and hours of frustration haha!