I'm not sure why, but i think it has something to do with the arrangment of orbitals.
Maybe someone else may know why.
is it to do with something about the amount of free orbitals because Zn2+ would become [Ar] 3d10 4s0. meaning that there would be only 4 orbitals that can be filled by the dative covalent bonds ie/ the 4s0 and the 4p0 which allows 4 dative covalent bonds?? (im guessing - seems like the only logical answer)
I'm using George Facer book to revise and I'm finding loads of extra information that is not in our specification Do we need the chemical reactions of phenylamine?
The main reaction of phenylamine that you should know is with Hcl and Nano2 to form benzene diazonium ion(chloride)
Also there are usual stuff like adding bromine - which is just the same as if you were adding bromine to phenol
then it goes through the same reactions as just normal aliphatic amine ( because dont forget there is reactions with the ring as the main constituent and then the ring as a side group)
I'm using George Facer book to revise and I'm finding loads of extra information that is not in our specification Do we need the chemical reactions of phenylamine?
I think you do. From the revision book I'm using you need to know: Its preparation and physical properties Reactions of the NH2 group as a base Reactions of the NH2 group with ethanoyl chloride Reactions of the NH2 group with Copper (II) ions Reactions of the NH2 group with Nitrous Acid The ring is activated the same way it is for phenol
The main reaction of phenylamine that you should know is with Hcl and Nano2 to form benzene diazonium ion(chloride)
Also there are usual stuff like adding bromine - which is just the same as if you were adding bromine to phenol
then it goes through the same reactions as just normal aliphatic amine ( because dont forget there is reactions with the ring as the main constituent and then the ring as a side group)
so:
amine + acid chloride => n-sub amide
amine + acid => salt
amine + water => amineh+ + oh-
thats all i can think of that i know
yeh marcus is right but mostly you have to know about the diazonium salt manufacture tbh (sodium nitrate and HCL making the HNO2 and HCL) They like these questions because there is alot to ask about as you have to keep it below 10degrees etc... also how to make it from nitrated benzene! soo yeh
can anyone explain to me why NH3 is a weaker base than CH3NH2??? doesnt make sense to me
Amines are bases because they pick up hydrogen ions on the lone pair on the nitrogen atom. In methylamine, the attractiveness of the lone pair is increased because of the way it interacts with the electrons of the ch3. the alkyl group "pushes" away its electrons so the nitrogen will be a little bit more delta negative this means it can pick up hydrogen more easily
Hey !! Whens a complex ion square planar and tetrahedral ? The book I am using says a coordination no. of 4 attaching to ligands and complete d-subshells is formed means tetrahedral and vice versa for square planar . I am confused I thought transition metals have incomplete d subshells ?
yeh marcus is right but mostly you have to know about the diazonium salt manufacture tbh (sodium nitrate and HCL making the HNO2 and HCL) They like these questions because there is alot to ask about as you have to keep it below 10degrees etc... also how to make it from nitrated benzene! soo yeh
Oh, I know the reactions of phenol and amine so basically all I need to do is combine them right? I thought adding sodium nitrate and HCL to phenylamine gives you benzenediazonium chloride instead of 'HNO2 and HCL' :/ Ahh I'm soo confused
Hey !! Whens a complex ion square planar and tetrahedral ? The book I am using says a coordination no. of 4 attaching to ligands and complete d-subshells is formed means tetrahedral and vice versa for square planar . I am confused I thought transition metals have incomplete d subshells ?
I remember my teacher saying that the reasoning behind it is beyond a level. As said in a couple of posts in the thread the only ones we should know as being square planar is [pt(nh3)2(cl2)] and [cu(cl)4]2- (Dont take my word for it)
Oh, I know the reactions of phenol and amine so basically all I need to do is combine them right? I thought adding sodium nitrate and HCL to phenylamine gives you benzenediazonium chloride instead of 'HNO2 and HCL' :/ Ahh I'm soo confused
no you may be thinking of phenol with benzenediazonium ion to make an azo dye.
Your right... Basically the reaction occurs in two stages this is because Hno2 is very unstable and needs to make in situ : Firstly you need to make the HnO2
is it to do with something about the amount of free orbitals because Zn2+ would become [Ar] 3d10 4s0. meaning that there would be only 4 orbitals that can be filled by the dative covalent bonds ie/ the 4s0 and the 4p0 which allows 4 dative covalent bonds?? (im guessing - seems like the only logical answer)
Yes, thats what I was thinking. But then I tried using the same logic with Cu2+ but It didnt seem to work.
Amines are bases because they pick up hydrogen ions on the lone pair on the nitrogen atom. In methylamine, the attractiveness of the lone pair is increased because of the way it interacts with the electrons of the ch3. the alkyl group "pushes" away its electrons so the nitrogen will be a little bit more delta negative this means it can pick up hydrogen more easily
when does the point come when adding alkyl groups has more impeding affects to basic action? e.g CH3CH2CH2NH2 is weaker...
when does the point come when adding alkyl groups has more impeding affects to basic action? e.g CH3CH2CH2NH2 is weaker...
it doesnt, they all have similar effect regardless of the number of alkyl group. Its only when it has a benzene ring when it gets weaker as the nitrogen interacts with the ring
is this from the CGP revision guide by any chance?
No, im looking at Jukeboxing's sheets with all of the reactions, to be honest im not that sure because it seems to be different depending on what book you read