What grades are people aiming for/wanting to get after that exam?
well i was aiming for 100ums but after that its likely ill only get over 85ums if im lucky. 8b) ****ed with me. maximum question ****ed with but i knew exactly how to do it but i thought the wrong of maximums and minimums .
this is why: Well, we wanted to find the maximum value of p(θ)
p(θ) = 4 / (12 + (6cosθ + 8sinθ))
In the previous question we found out that 6cosθ + 8sinθ = 10cos(θ - 0.927)
p(θ) = 4 / (12 + 10cos(θ - 0.927))
If we want to maximise p(θ), we want the denominator of the function to be as small as possible, therefore giving a higher value of p(θ)
So we can find the minimum of 10cos(θ - 0.927) which will be 10(-1) = -10
So now we get p(θ) = 4 / (12-10) = 4 / 2 = 2
The maximum value for p(θ) = 2
oh gosh... i put the value 1 for cos(theta - 0.927). do you remember what was the mark for this question, plus the part after this question altogether?