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AQA Unit 3 Mathematics 13 June 2012 - Unofficial Mark Scheme [43603H] [GCSE]

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Reply 60
Original post by lewisbee
yes but didn't he go over 180 degrees so therefore it has to be out of 360 degrees??


you're wrong :L
The bearings one was- 360-324= 36

Then do 180-36=144 because they're allied angles
Reply 62
Original post by Davelittle
The bearings one was- 360-324= 36

Then do 180-36=144 because they're allied angles

It was 342 not 324, but yes that is the method that I used.
Reply 63
Original post by Maths94
For question 15 where it was something like 3x+x2-10=0
What answers did use get and did you use trial and improvement?


no you had to use the quadratic formula given at the start of the booklet!!
Reply 64
Original post by gabyp

...


Many people have agreed that the answer posted is correct
Reply 65
Original post by gabyp



Question ?: (Vector Questions)
a) 1.5s as the ratio was 3:2
b) -s+t+1.5s= t+0.5s


Question ?: (x and y perimeter)
x=2.5y

2x+2y = perimeter

y=0.4x

^^thats wrong babe!!
if the perimeter is 2x + 2y and 2.5y = x, the experission of x would be: x = 7y
because 2x=5y and 5y + 2y = 7y you need to substitute 2.5y = x into the expression given!
therefore it is x = 7y


no that's wrong lol
What did you guys get for angle P, Q 12?

I got 53.13

Also angle x , question 14.

i got x = 124

for the sector and triangle question i got 12.57. I used 8 as the radius.

the second question (reading off the graph) i got -2.6, 2.8 (probably wrong)

third question (concrete) i got 14

fourth question (enlargement) i got 48 (??)

That's all i can remember
Reply 67
Original post by Kingboss
Does anyone know the answer for the volume of the cuboid question?I got that x was 1.5 or something

This was posted from The Student Room's Android App on my HTC Desire


x = 3
because the question was something like length = 5x + 1
and width = 2x + 3
^not sure if the correct expression
it said the difference between length and width was 7cm so you had to find the difference between length and width which was 3x - 2, therefore 3x - 2 = 7 , when worked out equals x = 3,
then you find the volume out which is: width x length x height
so gave the answer something like (not sure but...) 9 x 16 x 3 = 432
If, in a given mark scheme, it says to award a mark for working out, and you've put said working out inside the shape (a triangle in this case), will the examiner still award the mark?

Thanks.
Reply 69
Original post by Will2012
no that's wrong lol


opps my badd!! :smile:
Reply 70
Original post by PrinceUpsb
Many people have agreed that the answer posted is correct


oppss my bad sorry lol!! :smile:
Reply 71
Original post by the_googly
What about the bearing questions.

The question where one of the angles was 342? I got 18 as my answer for that.


nope it would have been : 360-342= 18 then 180-18=162 degrees :smile: 100% sure
Reply 72
Could anyone explain how you got 14 for the concrete slabs question? :s-smilie:
Reply 73
Original post by Dr.Monstaa
Could anyone explain how you got 14 for the concrete slabs question? :s-smilie:


50% of 3.8 = 1.9
10% = 0.38
5% = 0.19
1.9 + 0.19 = 2.09 (55%concrete)

then they had 6 loads of something, multiplied by 5 = 30

30 divided by 2.09 = 14.35.

i put 14.35 as my answers guys.. does it matter? cus it didnt ask for a rounded answer...
Reply 74
Can we just have ONE mark scheme instead of everyone posting about questions they thought was right
Reply 75
Original post by JamezA60
Can we just have ONE mark scheme instead of everyone posting about questions they thought was right


The original poster obviously can't memorise every single question that was in the paper so he/she is looking us to discuss the questions so that he/she can post up the 'official' 'unofficial' marks for the mark scheme.
Reply 76
Original post by xxcharlotteoxx
Does anyone know around what amount of marks i would need out of 80 to get myself an a*?? :smile:


72 :smile:
Reply 77
I got 1.5s for one answer and t=44 for another. Not sure which questions but I'm pretty sure they are right
Reply 78
For the question about why the angle is 118 degrees, was the correct answer 'alternate segment theorem' or that 'the larger shape is a cyclic quadrilateral and so opposite angles are equal to 180 degrees. With the opposite angle being 62 as a result of angles on a straight-line adding to 180, the angle is 118 degrees.'?

Either seem right to me...
Reply 79
Original post by Will2012
think the answer was 36.something :tongue:


36.36 was what I got :smile:

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