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C4 Q

http://store.aqa.org.uk/qual/gce/pdf/AQA-MPC4-W-QP-JUN11.PDF
http://store.aqa.org.uk/qual/gce/pdf/AQA-MPC4-W-MS-JUN11.PDF

Q8b, the final mark.

I can't seem to get from 1/(1-x) -1 to x/(1-x)

Can anyone help?
Reply 1
Avatar for raheem94
raheem94
13
Original post by uxa595
http://store.aqa.org.uk/qual/gce/pdf/AQA-MPC4-W-QP-JUN11.PDF
http://store.aqa.org.uk/qual/gce/pdf/AQA-MPC4-W-MS-JUN11.PDF

Q8b, the final mark.

I can't seem to get from 1/(1-x) -1 to x/(1-x)

Can anyone help?


11−x−1=11−x−1(1−x)1−x=1−(1−x)1−x=x1−x \displaystyle \frac1{1-x} - 1 = \frac1{1-x} - \frac{1(1-x)}{1-x} = \frac{1-(1-x)}{1-x} = \frac{x}{1-x}
Original post by uxa595
http://store.aqa.org.uk/qual/gce/pdf/AQA-MPC4-W-QP-JUN11.PDF
http://store.aqa.org.uk/qual/gce/pdf/AQA-MPC4-W-MS-JUN11.PDF

Q8b, the final mark.

I can't seem to get from 1/(1-x) -1 to x/(1-x)

Can anyone help?


11−x−1=1−1+x1−x=x1−x\dfrac{1}{1-x}-1=\dfrac{1-1+x}{1-x}=\dfrac{x}{1-x}
Reply 3
Avatar for uxa595
uxa595
OP
21
Original post by raheem94
11−x−1=11−x−1(1−x)1−x=1−(1−x)1−x=x1−x \displaystyle \frac1{1-x} - 1 = \frac1{1-x} - \frac{1(1-x)}{1-x} = \frac{1-(1-x)}{1-x} = \frac{x}{1-x}


Thanks :smile:

I'm surprised i managed 100 UMS on this one. The boundaries seem ridiculously low.
Woops, someone already replied!
Reply 5
Avatar for raheem94
raheem94
13
Original post by uxa595
Thanks :smile:

I'm surprised i managed 100 UMS on this one. The boundaries seem ridiculously low.


No problem.

I don't have much idea about AQA grade boundaries but well done :smile:
Reply 6
Avatar for Sagacious
Sagacious
13
dammit! by the time I figure out how to lay it our clearly it Latex, Raheem swoops in haha.

I got owned... again.

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