I agree with the "-N-Trimethyl" its the bit before that, I disagree with though.
Where are you getting the Propanoic acid from? That part could have been been an Aldehyde?
I would say its Propanamide N-trimthyl
Nice that covers the CH3CH2CON bit and ofcoure the N-(CH3)3 bit is correct?
That's just what I think though
you're correct, my bad. I would write it N-methyl propanamide though. Propanamide because its essentially an aldehyde with a amine group attached. got it.
you're correct, my bad. I would write it N-methyl propanamide though. Propanamide because its essentially an aldehyde with a amine group attached. got it.
Yeah I see what you mean, I hate naming it when they hace the N- makes everything complicated
Can someone explain on how to do the proton nmr stuff like working out integration values and integration ratios???
You'll be given the integration values in the exam so don't worry about that. To get the ratios, just get the lowest common multiple between the numbers and you're done.
You'll be given the integration values in the exam so don't worry about that. To get the ratios, just get the lowest common multiple between the numbers and you're done.
So thanks how would you do the 8 c) i) and ii) from the chem 4 jan 2006 paper from the old spec.
Unit 5..... So much memorising compare to unit 4 !! Any better ways to revise unit 5 ???
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Unit 5 isn't much memorising tbh. It's all about understanding what it going on. So make sure you get exactly what is happening, then question yourself..."but why is it doing that?" - it helps!!!
how did you get 5? thats the right answer. ii could only get 4
because you get 5 groups starting from the most electronegative substance the oxygen, so when you count the protons at every different occurring position along the chain the Hydrogen it is in will affect how many peaks there are. The 2 CH3 group on the second Carbon count as 1 for example.
because you get 5 groups starting from the most electronegative substance the oxygen, so when you count the protons at every different occurring position along the chain the Hydrogen it is in will affect how many peaks there are. The 2 CH3 group on the second Carbon count as 1 for example.
thanks but why don't the two ch2 groups count as one?