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How to factorise cubic expressions?

Ok so y = x^3 + x^2 - 2x

How do I do this :smile:

And x^3 - x^2

and x^3 = 9x


Basically I've used these questions because each one is different and uses different techniques :smile:

Thanks!!!! :biggrin:
Pull out common factors :smile:

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Reply 2
Have you done remainder theorem? I.e. f(x)=x3+x22x f(x) =x^3 + x^2 -2x , when f(y)=0f(y)=0, (x-y) is a factor.
Original post by Atheism
Have you done remainder theorem? I.e. f(x)=x3+x22x f(x) =x^3 + x^2 -2x , when f(y)=0f(y)=0, (x-y) is a factor.


Thats the factor theorem :smile:

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Reply 4
Original post by shadab786ahmed
Pull out common factors :smile:

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Original post by Atheism
Have you done remainder theorem? I.e. f(x)=x3+x22x f(x) =x^3 + x^2 -2x , when f(y)=0f(y)=0, (x-y) is a factor.



Original post by shadab786ahmed
Thats the factor theorem :smile:

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No I haven't :s-smilie:
only x is a common factor????
Reply 5
Original post by shadab786ahmed
Thats the factor theorem :smile:

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Sure, but the factor theorem is only a special case of the remainder theorem so it is the remainder theorem
Reply 6
Original post by Blueray2
No I haven't :s-smilie:
only x is a common factor????


Then take x out and you have a quadratic to factorise
Reply 7
Original post by TenOfThem
Then take x out and you have a quadratic to factorise


oh so x(x^2+x-2)

then I solve x^2+x-2=0
to get 2 x brackets :smile:

and the first x is just = 0
Original post by TenOfThem
Sure, but the factor theorem is only a special case of the remainder theorem so it is the remainder theorem


That makes sense :tongue: :colondollar:

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Reply 9
Original post by Blueray2
oh so x(x^2+x-2)

then I solve x^2+x-2=0
to get 2 x brackets :smile:

and the first x is just = 0


yes

remind me ... do you go to school and have a teacher or is this all you?
Reply 10
Original post by TenOfThem
Then take x out and you have a quadratic to factorise


Cheers I got it right :biggrin: Your amazing :colondollar:
Reply 11
since everything is in terms of x it's much easier you just pull out x and then factorize the quadratic.
Reply 12
Original post by TenOfThem
yes

remind me ... do you go to school and have a teacher or is this all you?


I go school, but the teacher doesn't help, he refuses to, and I get loads of H.w
but it's fine I got it right with your help :smile:
Reply 13
Original post by Blueray2
I go school, but the teacher doesn't help, he refuses to, and I get loads of H.w
but it's fine I got it right with your help :smile:


TenOfThem should be getting paid by your school as well as her own. :biggrin:
Original post by BabyMaths
TenOfThem should be getting paid by your school as well as her own. :biggrin:


LoL
Original post by TenOfThem
x


:eek: sorry! Didn't realise you were female :colondollar: I am on the app so cant see the signs!

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Reply 16
Original post by BabyMaths
TenOfThem should be getting paid by your school as well as her own. :biggrin:


:lol: I swear one day when I'm rich i'll make my own school which gives free tutoring :tongue:
Reply 17
Original post by BabyMaths
TenOfThem should be getting paid by your school as well as her own. :biggrin:



Original post by TenOfThem
LoL



Original post by shadab786ahmed
:eek: sorry! Didn't realise you were female :colondollar: I am on the app so cant see the signs!

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For the 2nd one I got
x^3 - x^2

= x(x^2-x)

what does (x^2-x) =
I mean in terms of x values to draw the sketchs :smile:
erm ....

x3x2=x2(x1)x^3-x^2 = x^2(x-1)
Reply 19
Original post by TenOfThem
erm ....

x3x2=x2(x1)x^3-x^2 = x^2(x-1)


lol yh my bad, was abt to edit that :smile:

Ok so x^2 = (x)(x)
so x = 0
and x =1
thanks I get it

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