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AS chemistry help

hi can someone please show me in stages how to complete this question i have done abit of it but have no idea if i'm goin on the right track

2.76g of Aluminium Chloride was dissolved in water and an excess of Silver Nitrate solution was added to give a percipitate of silver chloride

AlCl3(Aq) + 3AgNO3(Aq) --> Al(NO3)3(Aq) + 3AgCl(s)

What mass of SIlver chloride percipite would be formed (Al=27 Cl=35.5 Ag=108)
shanshine
hi can someone please show me in stages how to complete this question i have done abit of it but have no idea if i'm goin on the right track

2.76g of Aluminium Chloride was dissolved in water and an excess of Silver Nitrate solution was added to give a percipitate of silver chloride

AlCl3(Aq) + 3AgNO3(Aq) --> Al(NO3)3(Aq) + 3AgCl(s)

What mass of SIlver chloride percipite would be formed (Al=27 Cl=35.5 Ag=108)


1. Calculate the moles of AlCl3 (moles = mass/relative mass)

2. From the equation you see that 1 mole of AlCl3 makes 3 moles of silver chloride so multiply this by three to get moles of silver chloride.

3. Now multiply this value by the relative mass of AgCl to get the actual mass formed.

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