The Student Room Group
Reply 1
x=ut +1/2at^2
x1=12t+1/2(9.8)t^2=12t1+4.9t1^2 (1)
x2=20t+1/2(9.8)t^2=20t2+4.9t2^2 (2)
t2=t1+1
(2)=>x2=20(t1+1)+4.9(t1+1)^2=.......

When they will meet they will have made the same distance: =>(1)=(3)

=>12t1+4.9t1^2=(3) ....... And u find the result :P
Try modelling, with S=ut+1/2at^2, displacement of both particles. They will collide when their displacement equals each other.

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