you don't know that what you have written is equal to i, only that it is parallel to it.
your last line makes no sense. there is no equals sign. assuming you meant an equals sign instead of a plus sign.... does what you've written make any sense? can ANY amount of i vectors equal some amount of j vectors?
Hi, Basically if its saying that its parellel to the vector, i, then it means its horizontal right? so the j component must equal 0 (if it equalled anything else, the vector would be at an angle).
so 5-λ=0 λ=5
I think I'm right Hope it helps anyway. (apply the same thing to part b with the i component equating to 0)
Hi, Basically if its saying that its parellel to the vector, i, then it means its horizontal right? so the j component must equal 0 (if it equalled anything else, the vector would be at an angle).
so 5-λ=0 λ=5
I think I'm right Hope it helps anyway. (apply the same thing to part b with the i component equating to 0)
But how do you know that Vector I is horizontal and not at an angle ?
Thats what defines the i vector, sorry I don't how to better explain it but its the fundamentals of vector mechanics. Go to page 1 on your M1 book! The i component is the horizontal (x) component and the j component is the vertical (y) component.
as per ur working the line before last is 2i+5j+3iλ-jλ=i 3iλ-jλ=i-2i-5j λ(3i-j)=-i-5j λ=-i-5j/3i-j u can then simplify further if u want this answer is according 2 your working
His working is wrong, the top equation doesn't equal i. It is a multiple of i, but that doesn't really matter. When it says parallel to vector i, it means there is no j component, thats it.
His working is wrong, the top equation doesn't equal i. It is a multiple of i, but that doesn't really matter. When it says parallel to vector i, it means there is no j component, thats it.
the vector (2i + 5j) + λ(3i - j) is parallel to the unit vector i so it has no j component, so multiply out the brackets and collect the i terms together and the j terms together and set the j terms = 0 (because there is no j component).
the vector (2i + 5j) + λ(3i - j) is parallel to the unit vector i so it has no j component, so multiply out the brackets and collect the i terms together and the j terms together and set the j terms = 0 (because there is no j component).
no, you don't need the i values for this question. you collect the j terms so you have 5j - λj which = ( 5 - λ )j and then you set this equal to 0 and solve for λ.
no, you don't need the i values for this question. you collect the j terms so you have 5j - λj which = ( 5 - λ )j and then you set this equal to 0 and solve for λ.