The Student Room Group
Reply 1
You're on the right track, but you need to use the chain rule. Remember that cot3x=(cotx)3\cot^3 x = (\cot x)^3, so you can make the substitution u=cotxu = \cot x.
ahh, yes, that works now. C:

Much appreciated!
Reply 3
y=un[br][br]dydx=n×u×un1[br][br]u=1tanx[br] y = u^n[br][br]\dfrac{dy}{dx} = n\times u' \times u^{n-1}[br][br]u = \dfrac{1}{tanx}[br]

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