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help please
If someone has the new edexcel FP2 spec book the green one can you have a look at
question 31 on page 149
im stumped a little even tough i have have a page of working i cant get to the las bit
ive used dy/dt=dy/dx x dx/dt
question 31 on page 149
im stumped a little even tough i have have a page of working i cant get to the las bit
ive used dy/dt=dy/dx x dx/dt
ok here it is
2x(d^2x/dt^2) - 6(dx/dt)^2 = x^2 -3x^4
ito give d^2y/dt^2 + y =3 using substitution y=1/x^2
so i have this
dy/dt = dy/dx x dx/dt
d^2x/dt^2 = -x^3/2(d^2y/dt^2) - 3/2x^2(dy/dt)
dx/dt = -x^3/2(dy/dt)
sub those values in and i get this
-2y(d2^y/dt^2) - 6y^1/2(dy/dt) -3(dy/dt)^2 = 2y^2 - 6
but not sure how to cancel it further
2x(d^2x/dt^2) - 6(dx/dt)^2 = x^2 -3x^4
ito give d^2y/dt^2 + y =3 using substitution y=1/x^2
so i have this
dy/dt = dy/dx x dx/dt
d^2x/dt^2 = -x^3/2(d^2y/dt^2) - 3/2x^2(dy/dt)
dx/dt = -x^3/2(dy/dt)
sub those values in and i get this
-2y(d2^y/dt^2) - 6y^1/2(dy/dt) -3(dy/dt)^2 = 2y^2 - 6
but not sure how to cancel it further
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