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Ln|e^(x^2+2x)| = (x^2+2x)
logic123
if you have e^(x^2+2x) how do you somplify it does it become x^2 +2x?

Common sense says no. (Why would e^(x^2 + 2x) be equal to x^2 + 2x? What would be the point of the "e^"?)
Reply 3
sorry no what does e^(x^2+2lnx)
Reply 4
generalebriety
Common sense says no. (Why would e^(x^2 + 2x) be equal to x^2 + 2x? What would be the point of the "e^"?)

... or you could just take logs on both sides.
Reply 5
no what does e^(x^2+2lnx) its this one sos i mistyped
logic123
sorry no what does e^(x^2+2lnx)

Well, e^(a+b) = (e^a)*(e^b). And you should know that 2 ln x = ln(x^2). Can you do it from there?

Pheylan
... or you could just take logs on both sides.

"Both sides" of what? Last time I looked, "do __ to both sides" referred to operating on both sides of an equation to help you solve it. There's no equations here.
logic123
sorry no what does e^(x^2+2lnx)


e^(X^2) * e^ln|X^2|

e^(X^2)X^2
Reply 8
so it simplifys to x^2 +1 ??
Reply 9
ok just to check i had to intergrate 2x/1+x^2 does that give you x^2+2lnx
Reply 10
logic123
so it simplifys to x^2 +1 ??

no..ex2.x2e^{x^2}.x^2
Reply 11
no.. it wont. if you take the ln of the function then it would be x^4.. correct me if im wrong guys.. brain seems dead.
Reply 12
logic123
ok just to check i had to intergrate 2x/1+x^2 does that give you x^2+2lnx

no

make the substitutionu=x2+1 u=x^2+1
logic123
ok just to check i had to intergrate 2x/1+x^2 does that give you x^2+2lnx


Always keep an eye out for integrals of this type:

f(x)f(x)=lnf(x)+k\int \frac{f'(x)}{f(x)} = ln |f(x)| + k
Reply 14
why are we integrating though?
Tewari
why are we integrating though?

Because the OP keeps changing the question, and his latest one seems to involve integration.
logic123
if you have e^(x^2+2x) how do you somplify it does it become x^2 +2x?



The question is nonsense.

I have a similar nonsense question.

If you have 12 how do you simplify it to become 5?
Reply 17
haha, this is getting insane...

how about subtract 7 from the 12 to get 5?? ^.^
Tewari
haha, this is getting insane...

how about subtract 7 from the 12 to get 5?? ^.^


Simplify does not mean change the value. That's why my question and the OP's question are nonsense.
take the natural log of it, log base e and that should put it to the function you want. Which is what you wanted.

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