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Old 2 Weeks Ago: 4th November 2009 09:23 #1 
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Default domain of a function
 
Hi,

what is the domain of ( x^3 - x) ^1/4 ?

i thought it must be [0,infinity) but could there be other values that it cannot be?

also can i simplify this? maybe then i could see any other values

Thanks
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Old 2 Weeks Ago: 4th November 2009 09:26 #2 
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Default Re: domain of a function
 
Well, yes, try and factorize x^3 - x, and can you see where it is undefined (i.e. x^3 - x < 0)?
 
Old 2 Weeks Ago: 4th November 2009 09:26 #3 
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Default Re: domain of a function
 
Your answer's not quite right, but almost.

The function f(u) = u^{\frac{1}{4}} has the domain u \ge 0. Here, u = x^3 - x, so x^3 - x \ge 0. Solving this inequality for x will give you the domain of the function.

Spoiler:
 
Old 2 Weeks Ago: 4th November 2009 09:27 #4 
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Default Re: domain of a function
 
Can you factorise x^3-x? Does this help to see when you can't take a fourth root?
 
Old 2 Weeks Ago: 4th November 2009 09:29 #5 
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Default Re: domain of a function
 
looks like lolbridge has a 9am on a wednesday morning...
 
Old 2 Weeks Ago: 4th November 2009 09:30 #6 
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Default Re: domain of a function
 
We're all in lectures posting from our (i)phones.
 
Old 2 Weeks Ago: 4th November 2009 09:30 #7 
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Default Re: domain of a function
 
Originally Posted by Totally Tom
looks like lolbridge has a 9am on a wednesday morning...

they're actually teaching us how to count from 0 to infinity. can you believe that?
 
Old 2 Weeks Ago: 4th November 2009 09:40 #8 
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Default Re: domain of a function
 
i dont understand, if i factorise it i get x ( x^2 - x) >(or equal to) 0 ? so x>0, x>1 (or equal to in both cases.)

so then i can take the fourth root for all x>0
Old 2 Weeks Ago: 4th November 2009 09:51 #9 
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Default Re: domain of a function
 
Originally Posted by around
they're actually teaching us how to count from 0 to infinity. can you believe that?
sux to be you.
 
Old 2 Weeks Ago: 4th November 2009 09:53 #10 
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Default Re: domain of a function
 
Originally Posted by FPL67
i dont understand, if i factorise it i get x ( x^2 - x) >(or equal to) 0 ? so x>0, x>1 (or equal to in both cases.)

so then i can take the fourth root for all x>0
you've done factorised it wrong.
 
Old 2 Weeks Ago: 4th November 2009 13:48 #11 
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Default Re: domain of a function
 
oh yeah sorry, so it is x(x^2 -1) > 0
so x>0, x>1, x>-1 ? so my domain would be [-1,infinity)

(please note all > should be greater that or equal to signs)
Old 2 Weeks Ago: 4th November 2009 15:42 #12 
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Default Re: domain of a function
 
Originally Posted by Totally Tom
looks like lolbridge has a 9am on a wednesday morning...
10-12am Monday-Saturday This term at least.

"Lolbridge" is poor; at least call it "Lamebridge" or something
 
Old 2 Weeks Ago: 4th November 2009 16:18 #13 
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Default Re: domain of a function
 
domain is whatever you want, if x = -4, -60 still has 4th roots!

badly posed question =)
 
 
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