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Constant Acceleration Equations Help!

I just need some help attempting this uestion. I've attempted it myself but it appears to be wrong.

3)An object in free fall has a constant acceleration of 9,81ms-2. It goes past two light gates during it's fall, and the time interval between passing the 1st and 2nd gate is 0.269s. The distance between the two light gates is 1.36m.

a)What is the objects speed as it passes the 1st light gate?

- I seem to get 3.64ms-1 but that book says 3.74ms-1 so i'm obviously doing something wrong no?

b) At what height above the 1st light gate was it dropped?

-I can do this question theoretically easy using the answer from the speed obtained in a) so that's 0.67m if I use my incorrect answer of 3.64ms-1, compared to the books answer of 0.712m because they're answer for speed was 0.712m

Any help? Sorry if that was too long/confusing.
Reply 1
Avatar for ArVi
ArVi
13
a) I get 3.74ms-1 using: s=ut+0.5at2s = ut + 0.5at^2. Not sure where you went wrong.
b) Yeah, I get 0.712m (but your method seems correct).
ArVi
a) I get 3.74ms-1 using: s=ut+0.5at2s = ut + 0.5at^2. Not sure where you went wrong.
b) Yeah, I get 0.712m (but your method seems correct).


Yep, I just did it again, it seems I was inputting the numbers in the incorrect order on the calculator. My fault =] Thankx alot though

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